34

MS SQL SERVER 2008 を使用しており、次のデータがあります。

select * from account;

| PERIOD | ACCOUNT | VALUE |
----------------------------
|   2000 |   Asset |   205 |
|   2000 |  Equity |   365 |
|   2000 |  Profit |   524 |
|   2001 |   Asset |   142 |
|   2001 |  Equity |   214 |
|   2001 |  Profit |   421 |
|   2002 |   Asset |   421 |
|   2002 |  Equity |   163 |
|   2002 |  Profit |   325 |

私はそれらをこれにしたい：

| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
|   Asset |  205 |  142 |  421 |
|  Equity |  365 |  214 |  163 |
|  Profit |  524 |  421 |  325 |

use をクエリしようとしましpivot queryたが、値を使用する必要がaggregate functionあり、結果が適切ではありません。私は何をすべきか？

4

2 に答える 2

43 
SELECT *
FROM
(
SELECT [Period], [Account], [Value]
FROM TableName
) AS source
PIVOT
(
    MAX([Value])
    FOR [Period] IN ([2000], [2001], [2002])
) as pvt

別の方法、

SELECT ACCOUNT,
      MAX(CASE WHEN Period = '2000' THEN Value ELSE NULL END) [2000],
      MAX(CASE WHEN Period = '2001' THEN Value ELSE NULL END) [2001],
      MAX(CASE WHEN Period = '2002' THEN Value ELSE NULL END) [2002]
FROM tableName
GROUP BY Account
于 2013-01-31T04:18:33.150 に答える
7

これもチェックしてくださいxml path：pivot

SQLFIDDLE デモ

| ACCOUNT | 2000 | 2001 | 2002 |
--------------------------------
|   Asset |  205 |  142 |  421 |
|  Equity |  365 |  214 |  163 |
|  Profit |  524 |  421 |  325 |

DECLARE @cols AS NVARCHAR(MAX),
    @query  AS NVARCHAR(MAX)

SET @cols = STUFF((SELECT distinct ',' + QUOTENAME(c.period) 
            FROM demo c
            FOR XML PATH(''), TYPE
            ).value('.', 'NVARCHAR(MAX)') 
        ,1,1,'')

set @query = 'SELECT account, ' + @cols + ' from 
            (
                select account
                    , value
                    , period
                from demo
           ) x
            pivot 
            (
                 max(value)
                for period in (' + @cols + ')
            ) p '


execute(@query)
于 2013-01-31T04:47:29.257 に答える