1

列の値（以下に表示）に基づいて申請者をグループ 化し、そのグループの数を見つける必要がある状況があります。現在、クエリは、カウントが0を超える列のみを返しています。

すべてのグループとそのカウントがゼロとして表示されるように、クエリにどのような変更を加える必要がありますか？

クエリ：

select Applicant_info.range as [Income Range], count(*) as [Total Students],order_number =
          CASE range
             WHEN 'Did not specify' THEN '1'
             WHEN '0-25000' THEN '2'
             WHEN '25001-50000' THEN '3'
             WHEN '50001-75000' THEN '4'
             WHEN '75001-100000' THEN '5'
             WHEN '100001-200000' THEN '6'
             WHEN '200000 and Above' THEN '7'
          END
    from (
      select case  
        when Annual_Income is null or Annual_Income = '' then 'Did not specify' 
        when Annual_Income between 0 and 25000 then '0-25000'
        when Annual_Income between 25001 and 50000 then '25001-50000'
        when Annual_Income between 50001 and 75000 then '50001-75000'
        when Annual_Income between 75001 and 100000 then '75001-100000'
        when Annual_Income between 100001 and 200000 then '100001-200000'
        when Annual_Income > 200000 then '200000 and Above'
        end as range
      from Applicant_info)Applicant_info
    group by Applicant_info.range
    order by order_number
4

2 に答える 2

2

次のように、それぞれに個別のCASE式を使用します。

Select 
  range as [Income Range], 
  SUM(CASE when Annual_Income is null or Annual_Income = '' then END) AS 'Did not specify',
  SUM(CASE when Annual_Income between 0 and 25000 then 1 ELSE 0 END) AS '0-25000',
  SUM(CASE when Annual_Income between 25001 and 50000 then 1 ELSE 0 END) AS '25001-50000',
  SUM(CASE when Annual_Income between 50001 and 75000 then 1 ELSE 0END) AS  '50001-75000',
  SUM(CASE when Annual_Income between 75001 and 100000 then 1 ELSE 0 END) AS  '75001-100000',
  SUM(CASE when Annual_Income between 100001 and 200000 then 1 ELSE 0END) AS  '100001-200000',
  SUM(CASE when Annual_Income > 200000 then 1 ELSE 0 END) AS  '200000 and Above'
from Applicant_info
GROUP BY range;

注：このSUM関数は、合計が0または1であるため、実際にはカウントです。

于 2013-02-04T06:49:10.410 に答える
1

外部結合とルックアップテーブルを使用して、カウントがゼロの場合でもすべての範囲が含まれるようにすることができます。

SELECT C.[Range], COUNT(B.[Income_Band]) AS [Count]
FROM Applicant_info
CROSS APPLY
(
    SELECT
        CASE
            WHEN Annual_Income IS NULL OR ISNUMERIC(Annual_Income) = 0 THEN 1
            WHEN Annual_Income > 200000 THEN 7
            WHEN Annual_Income > 100000 THEN 6
            WHEN Annual_Income > 75000  THEN 5
            WHEN Annual_Income > 50000  THEN 4
            WHEN Annual_Income > 25000  THEN 3
            WHEN Annual_Income >= 0  THEN 2
            ELSE 1
        END AS [Income_Band]
) B
RIGHT JOIN
(
    SELECT 1 AS [Income_Band], 'Did not specify' AS [Range]
    UNION SELECT 2, '0-25000'
    UNION ALL SELECT 3, '25001-50000'
    UNION ALL SELECT 4, '50001-75000'
    UNION ALL SELECT 5, '75001-100000'
    UNION ALL SELECT 6, '100001-200000'
    UNION ALL SELECT 7, '200000 and Above'
) C
    ON C.[Income_Band] = B.[Income_Band]
GROUP BY C.[Range], C.[Income_Band]
ORDER BY C.[Income_Band]
于 2013-02-04T09:10:49.463 に答える