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Quote があり、その Quote の最後の 3 つのメモを 1 行にまとめたいと考えています。引用符から上位 3 つを選択すると、QuoteNote テーブルが作成されます。

QuoteNoteID       QuoteID      Note        NoteAreaID
     1               1         Test            2
     2               1         Test2           1
     3               1         Test3           1

このテーブルを選択すると、必要な情報が返されます

SELECT q.QuoteNoteID, q.QuoteID, q.Note, q.NoteAreaID, n.Description AS NoteAreaDesc
FROM Quote q INNER JOIN QuoteNote n ON n.QuoteID = q.QuoteID

これは私に与えます

QuoteNoteID       QuoteID      Note        NoteAreaID        NoteAreaDesc
     1               1         Test            2               Internal
     2               1         Test2           1               External
     3               1         Test3           1               External

今私がしたいのは、これを1行に入れることだけです

QuoteID    Note1    Note2    Note3    NoteAreaID1     NoteAreaID2    NoteAreaID3    NoteAreaDesc1    NoteAreaDesc2      NoteAreaDesc3
  1         Test     Test2   Tes3         2                1              1           Internal            External       External

助けていただければ幸いです、ありがとう

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1 に答える 1

2

これはあなたのために働くはずです：

WITH QuoteNotes AS
(   SELECT  QuoteNote.QuoteNoteID, 
            Quote.QuoteID, 
            QuoteNote.Note, 
            QuoteNote.NoteAreaID, 
            [NoteAreaDesc] = QuoteNote.Description,
            [QuoteNoteNumber] = ROW_NUMBER() OVER(PARTITION BY Quote.QuoteID ORDER BY QuoteNote.QuoteNoteID)
    FROM    Quote
            INNER JOIN QuoteNote
                ON QuoteNote.QuoteID = Quote.QuoteID
)
SELECT  QuoteID,
        [Note1] = MAX(CASE WHEN QuoteNoteNumber = 1 THEN Note END),
        [Note2] = MAX(CASE WHEN QuoteNoteNumber = 2 THEN Note END),
        [Note3] = MAX(CASE WHEN QuoteNoteNumber = 3 THEN Note END),
        [NoteAreaID1] = MAX(CASE WHEN QuoteNoteNumber = 1 THEN NoteAreaID END),
        [NoteAreaID2] = MAX(CASE WHEN QuoteNoteNumber = 2 THEN NoteAreaID END),
        [NoteAreaID3] = MAX(CASE WHEN QuoteNoteNumber = 3 THEN NoteAreaID END),
        [NoteAreaDesc1] = MAX(CASE WHEN QuoteNoteNumber = 1 THEN NoteAreaDesc END),
        [NoteAreaDesc2] = MAX(CASE WHEN QuoteNoteNumber = 2 THEN NoteAreaDesc END),
        [NoteAreaDesc3] = MAX(CASE WHEN QuoteNoteNumber = 3 THEN NoteAreaDesc END)
FROM    QuoteNotes
GROUP BY QuoteID;

SQL Fiddle の例

または

WITH QuoteNotes AS
(   SELECT  QuoteNote.QuoteNoteID, 
            Quote.QuoteID, 
            QuoteNote.Note, 
            QuoteNote.NoteAreaID, 
            [NoteAreaDesc] = QuoteNote.Description,
            [QuoteNoteNumber] = ROW_NUMBER() OVER(PARTITION BY Quote.QuoteID ORDER BY QuoteNote.QuoteNoteID)
    FROM    Quote
            INNER JOIN QuoteNote
                ON QuoteNote.QuoteID = Quote.QuoteID
)
SELECT  q1.QuoteID,
        [Note1] = q1.Note,
        [Note2] = q2.Note,
        [Note3] = q3.Note,
        [NoteAreaID1] = q1.NoteAreaID,
        [NoteAreaID2] = q2.NoteAreaID,
        [NoteAreaID3] = q3.NoteAreaID,
        [NoteAreaDesc1] = q1.NoteAreaDesc,
        [NoteAreaDesc2] = q2.NoteAreaDesc,
        [NoteAreaDesc3] = q3.NoteAreaDesc
FROM    QuoteNotes q1
        LEFT JOIN QuoteNotes q2
            ON q1.QuoteID = q2.QuoteID
            AND q2.QuoteNoteNumber = 2
        LEFT JOIN QuoteNotes q3
            ON q1.QuoteID = q3.QuoteID
            AND q3.QuoteNoteNumber = 3 -- changed this to be 3
WHERE   q1.QuoteNoteNumber = 1;

どちらも同じ結果が得られるはずですが、一方が他方よりも優れたパフォーマンスを発揮する場合があります。

SQL Fiddle の例

于 2013-02-08T10:28:00.363 に答える