1

これは、dput() を使用した私のデータフレームです。

structure(list(Year = 1900:1903, Top.10..income.share = structure(c(82L, 
81L, 76L, 75L), .Label = c("", "30,3", "30,65", "30,8", "31,3", 
"31,37", "31,38", "31,4", "31,5", "31,51", "31,52", "31,55", 
"31,62", "31,64", "31,66", "31,67", "31,69", "31,75", "31,77", 
"31,8", "31,81", "31,82", "31,85", "31,9", "31,98", "32,01", 
"32,03", "32,04", "32,05", "32,07", "32,11", "32,12", "32,2", 
"32,35", "32,36", "32,42", "32,43", "32,44", "32,5", "32,62", 
"32,64", "32,67", "32,72", "32,82", "32,87", "33,02", "33,22", 
"33,4", "33,69", "33,72", "33,76", "33,87", "33,95", "34,25", 
"34,4", "34,57", "34,62", "34,71", "35,49", "36,3", "36,48", 
"37,26", "37,3", "37,73", "37,77", "37,78", "37,84", "37,92", 
"38,01", "38,1", "38,2", "38,38", "38,4", "38,47", "38,52", "38,59", 
"38,6", "38,63", "38,84", "38,91", "38,99", "39,13", "39,31", 
"39,48", "39,6", "39,82", "39,9", "40,29", "40,54", "40,59", 
"40,75", "41,02", "41,16", "41,52", "41,73", "41,98", "42,12", 
"42,23", "42,36", "42,67", "42,76", "42,86", "42,95", "43", "43,07", 
"43,11", "43,26", "43,35", "43,39", "43,64", "43,76", "44,07", 
"44,17", "44,4", "44,43", "44,57", "44,67", "44,77", "44,94", 
"45,03", "45,16", "45,47", "45,5", "45,67", "45,96", "46,09", 
"46,3", "46,35", "46,54"), class = "factor")), .Names = c("Year", 
"Top.10..income.share"), row.names = c(NA, 4L), class = "data.frame")

私の sessionInfo():

R version 2.15.0 (2012-03-30)
Platform: x86_64-apple-darwin9.8.0/x86_64 (64-bit)

locale:
[1] de_DE.UTF-8/de_DE.UTF-8/de_DE.UTF-8/C/de_DE.UTF-8/de_DE.UTF-8

attached base packages:
[1] stats     graphics  grDevices utils     datasets  methods   base     

loaded via a namespace (and not attached):
[1] rstudio_0.97.248 tools_2.15.0  

私がやりたいことは、Top10 列に対して Year 列をプロットすることです。
しかし、かなりの数の欠損値があるため、グラフはかなりひどいものに見えます。
これまでにこれをプロットするために書いたコードを次に示します。

require(stats)

tid_a = read.csv("tid-a.csv", header=TRUE, sep=";")
germany <- tid_a[1:111, ]
usa <- tid_a[112:210, ]

germany_year <- germany[, 2]
germany_top10 <- na.omit(germany[, 3])

plot(germany_year, germany_top10, type="l")

欠損値を省略するためにオンラインで見つけたいくつかの例を試しましたが、私は初心者であり、機能させることができません。

4

1 に答える 1

2

この質問は再現できませんが、次のようなものはうまくいくはずです:

gdat <- na.omit(subset(germany,select=c(Year,Top10)))
plot(Top10~Year,data=gdat,type="l")

(subsetこの方法での の使用はかなりまれです --germany[,c("Year","Top10")]より一般的です -- しかし、私はそれが読みやすいので気に入っています。より単純なバージョンは ですが、データ フレームの任意の列でs を含むplot(...,data=na.omit(germany))行を省略します。)NA

于 2013-02-10T18:49:17.773 に答える