0

「単一の JavaScript オブジェクト」を作成したい JSON オブジェクトの配列があります。Python または JavaScript のアイデアをいただければ幸いです。実際、この種の質問を説明する (または Google で検索する) のに適切な用語が何であるかさえ、私にはわかりません。ありがとう！

元のリストは次のようになります。

[
{
    "State_Code": "01",
    "County_Code": "000",
    "State_Abbrv": "AL",
    "County_Name": "ALABAMA",
    "DATA": "12345"

},
{
    "State_Code": "01",
    "County_Code": "001",
    "State_Abbrv": "AL",
    "County_Name": "AUTAUGA COUNTY",
    "DATA": "123"

},
{
    "State_Code": "01",
    "County_Code": "003",
    "State_Abbrv": "AL",
    "County_Name": "BALDWIN COUNTY",
    "DATA": "321"

},
{
    "State_Code": "02",
    "County_Code": "000",
    "State_Abbrv": "AK",
    "County_Name": "ALASKA",
    "DATA": "98765"

},
{
    "State_Code": "02",
    "County_Code": "013",
    "State_Abbrv": "AK",
    "County_Name": "ALEUTIANS EAST BOROU",
    "DATA": "456"

},

..............  ]

そして、私はそれを次のようにしたい:

{
    "name": "USA",
    "children": [
        {
            "name": "ALABAMA",
            "children": [
                {
                    "name": "AUTAUGA COUNTY",
                    "DATA": 123
                },
                {
                    "name": "BALDWIN COUNTY",
                    "DATA": 321
                }
            ]
        },
        {
            "name": "ALASKA",
            "children": [
                {
                    "name": "ALEUTIANS EAST BOROU",
                    "DATA": 456
                }
            ]
        }
        .............
    ]
}

私はこの種のアイデアのような Python ループを使用しようとしています (タイプミスをお詫びします。今夜修正します)。

runningListCounty = []
tempD = defaultdict(dict)
tempDCounty = defaultdict(dict)
i = 0
for l in listOfJson:
  if l['County_Code'] == '000'
      tempD['name'] = l['County_Name']
      if i > 0: #only do this after the first loop
         tempD['children'] = runningListCounty 
         runningList.append(tempD)       
         runningListCounty = []
         tempD = defaultdict(dict)
  else:
      tempDCounty = defaultdict(dict)
      tempDCounty['name'] = l['County_Name']
      tempDCounty['DATA'] = l['DATA']
      runningListCounty.append(tempDCounty)
  i = i + 1
4

3 に答える 3

0

Javascript ソリューション:

デモ

var data = [
{
    "State_Code": "01",
    "County_Code": "000",
    "State_Abbrv": "AL",
    "County_Name": "ALABAMA",
    "DATA": "12345"

},
{
    "State_Code": "01",
    "County_Code": "001",
    "State_Abbrv": "AL",
    "County_Name": "AUTAUGA COUNTY",
    "DATA": "123"

},
{
    "State_Code": "01",
    "County_Code": "003",
    "State_Abbrv": "AL",
    "County_Name": "BALDWIN COUNTY",
    "DATA": "321"

},
{
    "State_Code": "02",
    "County_Code": "000",
    "State_Abbrv": "AK",
    "County_Name": "ALASKA",
    "DATA": "98765"

},
{
    "State_Code": "02",
    "County_Code": "013",
    "State_Abbrv": "AK",
    "County_Name": "ALEUTIANS EAST BOROU",
    "DATA": "456"

}
];

var newData = { name : 'USA', children : [] };

for(var i=0; i<data.length; i++) {
    if(data[i].County_Code == "000") {
        newData.children.push({ name : data[i].County_Name, state_code : data[i].State_Code, children : [] });
    }
}

for(var i=0; i<data.length; i++) {
    if(data[i].County_Code != "000") {
        for(var x=0; x<newData.children.length; x++) {
            if(data[i].State_Code == newData.children[x].state_code) {
                newData.children[x].children.push({ name : data[i].County_Name, data : data[i].DATA });
            }
        }
    }
}

console.log(newData); // or convert to JSON with  JSON.stringify(newData)

結果newDataは次のとおりです。

{
    "name": "USA",
    "children": [
        {
            "name": "ALABAMA",
            "state_code": "01",
            "children": [
                {
                    "name": "AUTAUGA COUNTY",
                    "data": "123"
                },
                {
                    "name": "BALDWIN COUNTY",
                    "data": "321"
                }
            ]
        },
        {
            "name": "ALASKA",
            "state_code": "02",
            "children": [
                {
                    "name": "ALEUTIANS EAST BOROU",
                    "data": "456"
                }
            ]
        }
    ]
}
于 2013-02-11T17:20:13.857 に答える
-1

Javascript ソリューション

ここにフィドルがあります： JSFIDDLE

コードは次のとおりです。

var statesObj = JsonSource,
    finalObj = {
        USA : {
            name: "USA",
            children: []
        }
    };
for (var st = 0; st < statesObj.length; ++st) {
    // First the states
    if( statesObj[st].County_Code === "000") {
        var newState = {
            name: statesObj[st].County_Name,
            abbrv: statesObj[st].State_Abbrv,
            children: []
        };
        finalObj.USA.children.push(newState);
    }
}

for (var st = 0; st < statesObj.length; ++st) {
    // Now the rest
    if( statesObj[st].County_Code !== "000") {
        var newChild = {
            name: statesObj[st].County_Name,
            data: statesObj[st].DATA
        };
        for (var sub in finalObj.USA.children) {
            if (finalObj.USA.children.hasOwnProperty(sub) &&
                finalObj.USA.children[sub].abbrv === statesObj[st].State_Abbrv) {
                finalObj.USA.children[sub].children.push(newChild);
                break;
            }
        }
    }
}

var finalJson = JSON.stringify(finalObj);
console.log(finalJson);
于 2013-02-11T17:13:28.403 に答える