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3つのテーブル（TABLE_A、TABLE_B、TABLE_C）があり、C_MAIN_REFでそれらを結合しています。TABLE_Bには複数のエントリがあり、返されるのは1つだけですが、どちらでも構いません。

何か案は？

編集：

SELECT C.C_UNIT_CODE as BU,'EPLC' as PRODUCT, A.BENE_NM as CUSTOMER, A.C_MAIN_REF,
        A.C_TRX_REF, A.PRES_CCY, TO_CHAR(A.PRES_AMT) AS PRES_AMT, A.PRES_DT AS PRES_DATE,
        A.DOC_STAT, '' AS APPL_RESPONSE, A.SETTLE_STATUS as SETTLE_STATUS 
    FROM EPLC_EM_NEGO A
    INNER JOIN CPYT_SCHEDULE B
           ON a.C_MAIN_REF = b.C_MAIN_REF AND ROWNUM =1
    INNER JOIN EPLC_MASTER C
            ON a.C_MAIN_REF = c.C_MAIN_REF
    WHERE a.CLS_DRWG_FLG = 'NO' AND b.CPYT_UNPAID_FLAG = 'T'

上記は私が使用している現在のクエリですが、問題は、CPYT_SCHEDULEに複数のエントリがあり、結合にはCPYT_SCHEDULEテーブルの1行しか含まれないことです。

現在上記の返品

BU   PRODUCT CUSTOMER               C_MAIN_REF   C_TRX_REF        PRES_CCY PRES_AMT  PRES_DATE DOC_STAT     SETTLE_STATUS
------------ ---------------------------------------------------- -------- --------- --------- ------------ -------------
GB01 EPLC    Finance Customer No. 5 XL000053GB01 XL000053GB01-01  USD      90000     24-AUG-12 COMPLIANT    Settle      
GB01 EPLC    Finance Customer No. 5 XL000053GB01 XL000053GB01-01  USD      90000     24-AUG-12 COMPLIANT    Settle       
GB01 EPLC    Finance Customer No. 5 XL000053GB01 XL000053GB01-01  USD      90000     24-AUG-12 COMPLIANT    Settle       
GB01 EPLC    Finance Customer No. 5 XL000053GB01 XL000053GB01-01  USD      90000     24-AUG-12 COMPLIANT    Settle

しかし、望ましい出力は

BU   PRODUCT CUSTOMER               C_MAIN_REF   C_TRX_REF        PRES_CCY PRES_AMT  PRES_DATE DOC_STAT     SETTLE_STATUS
------------ ---------------------------------------------------- -------- --------- --------- ------------ -------------
GB01 EPLC    Finance Customer No. 5 XL000053GB01 XL000053GB01-01  USD      90000     24-AUG-12 COMPLIANT    Settle
4

2 に答える 2

3

このようなもの：

SELECT C.C_UNIT_CODE as BU,
       'EPLC' as PRODUCT, 
       A.BENE_NM as CUSTOMER, 
       A.C_MAIN_REF,
       A.C_TRX_REF, 
       A.PRES_CCY, 
       TO_CHAR(A.PRES_AMT) AS PRES_AMT, 
       A.PRES_DT AS PRES_DATE,
       A.DOC_STAT, 
       '' AS APPL_RESPONSE, 
       A.SETTLE_STATUS as SETTLE_STATUS 
FROM EPLC_EM_NEGO A
INNER JOIN (select cs.*, 
                   row_number() over (partition by C_MAIN_REF) as rn
            from CPYT_SCHEDULE cs) b 
       ON a.C_MAIN_REF = b.C_MAIN_REF AND b.rn = 1
INNER JOIN EPLC_MASTER C
        ON a.C_MAIN_REF = c.C_MAIN_REF
WHERE a.CLS_DRWG_FLG = 'NO' 
  AND b.CPYT_UNPAID_FLAG = 'T'
于 2013-02-20T11:50:16.790 に答える
1

すべての回答と入力に感謝します。

SELECT C.C_UNIT_CODE as BU,'EPLC' as PRODUCT, A.BENE_NM as CUSTOMER, A.C_MAIN_REF, A.C_TRX_REF, A.PRES_CCY, TO_CHAR(A.PRES_AMT) AS PRES_AMT, A.PRES_DT AS PRES_DATE, A.DOC_STAT, '' AS APPL_RESPONSE, A.SETTLE_STATUS as SETTLE_STATUS
FROM E_EM_NEGO A, EPLC_MASTER C
WHERE a.CLS_DRWG_FLG = 'NO' AND a.C_MAIN_REF = c.C_MAIN_REF
     AND a.C_MAIN_REF = (
     SELECT C_MAIN_REF FROM CPYT_SCHEDULE B
     WHERE B.CPYT_UNPAID_FLAG = 'T' AND b.C_MAIN_REF = a.C_MAIN_REF AND rownum=1)
于 2013-02-20T14:17:11.000 に答える