2

行 ID、経度、緯度、ビジネス名、URL、キャプションを含むテーブルがあります。これは次のようになります。

rowID | long  | lat |  businessName | url | caption

  1      20     -20     Pizza Hut   yum.com  null

重複をすべて削除し、URL があるものだけを保持する (最優先)、または URL がない場合にキャプションがあるものを保持し (2 番目の優先順位)、残りを削除するにはどうすればよいですか?

4

6 に答える 6

4

この解決策は、先週の「Stack Overflow で学んだこと」によってもたらされました。

DELETE restaurant
WHERE rowID in 
(SELECT rowID
    FROM restaurant
    EXCEPT
    SELECT rowID 
    FROM (
        SELECT rowID, Rank() over (Partition BY BusinessName, lat, long ORDER BY url DESC, caption DESC ) AS Rank
        FROM restaurant
        ) rs WHERE Rank = 1)

警告: 実際のデータベースでこれをテストしていません

于 2008-09-30T01:25:49.430 に答える
3

これが私のループテクニックです。これはおそらく主流ではないという理由で否決されるでしょう - そして私はそれでクールです.

DECLARE @LoopVar int

DECLARE
  @long int,
  @lat int,
  @businessname varchar(30),
  @winner int

SET @LoopVar = (SELECT MIN(rowID) FROM Locations)

WHILE @LoopVar is not null
BEGIN
  --initialize the variables.
  SELECT 
    @long = null,
    @lat = null,
    @businessname = null,
    @winner = null

  -- load data from the known good row.  
  SELECT
    @long = long,
    @lat = lat,
    @businessname = businessname
  FROM Locations
  WHERE rowID = @LoopVar

  --find the winning row with that data
  SELECT top 1 @Winner = rowID
  FROM Locations
  WHERE @long = long
    AND @lat = lat
    AND @businessname = businessname
  ORDER BY
    CASE WHEN URL is not null THEN 1 ELSE 2 END,
    CASE WHEN Caption is not null THEN 1 ELSE 2 END,
    RowId

  --delete any losers.
  DELETE FROM Locations
  WHERE @long = long
    AND @lat = lat
    AND @businessname = businessname
    AND @winner != rowID

  -- prep the next loop value.
  SET @LoopVar = (SELECT MIN(rowID) FROM Locations WHERE @LoopVar < rowID)
END
于 2008-09-29T22:13:07.473 に答える
1

セットベースのソリューション：

delete from T as t1
where /* delete if there is a "better" row
         with same long, lat and businessName */
  exists(
    select * from T as t2 where
      t1.rowID <> t2.rowID
      and t1.long = t2.long
      and t1.lat = t2.lat
      and t1.businessName = t2.businessName 
      and
        case when t1.url is null then 0 else 4 end
          /* 4 points for non-null url */
        + case when t1.businessName is null then 0 else 2 end
          /* 2 points for non-null businessName */
        + case when t1.rowID > t2.rowId then 0 else 1 end
          /* 1 point for having smaller rowId */
        <
        case when t2.url is null then 0 else 4 end
        + case when t2.businessName is null then 0 else 2 end
        )
于 2008-09-29T22:34:37.717 に答える
1 
delete MyTable
from MyTable
left outer join (
        select min(rowID) as rowID, long, lat, businessName
        from MyTable
        where url is not null
        group by long, lat, businessName
    ) as HasUrl
    on MyTable.long = HasUrl.long
    and MyTable.lat = HasUrl.lat
    and MyTable.businessName = HasUrl.businessName
left outer join (
        select min(rowID) as rowID, long, lat, businessName
        from MyTable
        where caption is not null
        group by long, lat, businessName
    ) HasCaption
    on MyTable.long = HasCaption.long
    and MyTable.lat = HasCaption.lat
    and MyTable.businessName = HasCaption.businessName
left outer join (
        select min(rowID) as rowID, long, lat, businessName
        from MyTable
        where url is null
            and caption is null
        group by long, lat, businessName
    ) HasNone 
    on MyTable.long = HasNone.long
    and MyTable.lat = HasNone.lat
    and MyTable.businessName = HasNone.businessName
where MyTable.rowID <> 
        coalesce(HasUrl.rowID, HasCaption.rowID, HasNone.rowID)
于 2008-09-29T22:43:44.217 に答える
1

別の回答に似ていますが、ランクではなく行番号に基づいて削除したいと考えています。同様に、一般的なテーブル式と混合します。


;WITH GroupedRows AS
(   SELECT rowID, Row_Number() OVER (Partition BY BusinessName, lat, long ORDER BY url DESC, caption DESC) rowNum 
    FROM restaurant
)
DELETE r
FROM restaurant r
JOIN GroupedRows gr ON r.rowID = gr.rowID
WHERE gr.rowNum > 1
于 2008-09-30T09:36:28.687 に答える
0

可能であれば、ホモジナイズしてから重複を除去できますか?

ステップ1：

UPDATE BusinessLocations
SET BusinessLocations.url = LocationsWithUrl.url
FROM BusinessLocations
INNER JOIN (
  SELECT long, lat, businessName, url, caption
  FROM BusinessLocations 
  WHERE url IS NOT NULL) LocationsWithUrl 
    ON BusinessLocations.long = LocationsWithUrl.long
    AND BusinessLocations.lat = LocationsWithUrl.lat
    AND BusinessLocations.businessName = LocationsWithUrl.businessName

UPDATE BusinessLocations
SET BusinessLocations.caption = LocationsWithCaption.caption
FROM BusinessLocations
INNER JOIN (
  SELECT long, lat, businessName, url, caption
  FROM BusinessLocations 
  WHERE caption IS NOT NULL) LocationsWithCaption 
    ON BusinessLocations.long = LocationsWithCaption.long
    AND BusinessLocations.lat = LocationsWithCaption.lat
    AND BusinessLocations.businessName = LocationsWithCaption.businessName

ステップ 2: 重複を削除します。

于 2008-09-29T22:23:08.930 に答える