2

にリンクされているいくつかの派生テーブルに基づいていくつかの計算を行うこのクエリがありますINNER JOIN。

現時点では、WHERE一度に 1 つの ID を引き出す句があります。しかし、どうすればすべてのIDをリストすることができますか?

GROUP BYいろいろなところを調べてみましたがわかりません。

これまでの私のクエリは次のとおりです。

SELECT 
equipment_id, 
service_duration,
available_duration,
(available_duration / service_duration)*100 AS availability
FROM (
SELECT
SUM(service_end_time - service_start_time) AS service_duration
FROM(   
    SELECT equipment_id, 
    (CASE  
    END) AS service_start_time,
    (CASE  
    END) AS service_end_time
FROM t1 
WHERE equipment_id = 'EX123' 
  )AS A
) AS B
JOIN(
SELECT equipment_id, 
       SUM(available_end_time - available_start_time) AS available_duration
FROM (
    SELECT equipment_id,  
    (CASE 
    END) AS available_start_time,
    (CASE       
    END) AS available_end_time
FROM t2 
WHERE equipment_id = 'EX123'
  ) AS C
) AS D
ON equipment_id=D.equipment_id

私がやりたいのは、WHERE句をGROUP BYすべてのIDをリストするなどに置き換えることですが、それを機能させることは私のスキルレベルを超えています...どんな助けも大歓迎です:)

4

2 に答える 2

2

以下を試してください：

    SELECT 
    equipment_id, service_duration, available_duration,
    (available_duration / service_duration)*100 AS availability
    FROM 
    (
            SELECT equipment_id,
            SUM(service_end_time - service_start_time) AS service_duration
            FROM
            (   
                    SELECT equipment_id, 
                        (CASE ... END) AS service_start_time,
                        (CASE  ...  END) AS service_end_time
                    FROM t1         
            ) AS A
            GROUP BY equipment_id
    ) AS B
    JOIN
    (
            SELECT equipment_id, 
            SUM(available_end_time - available_start_time) AS available_duration
            FROM 
            (
                SELECT equipment_id,  
                (CASE ... END) AS available_start_time,
                (CASE ... END) AS available_end_time
                FROM t2         
            ) AS C
            GROUP BY equipment_id
    ) AS D
    ON equipment_id=D.equipment_id
于 2013-03-01T12:51:53.230 に答える
1

これを試してください（私のフィールド名をあなたのフィールド名に置き換えてください）：

SELECT 
    a.emp_id, 
    service_duration,
    available_duration 

FROM 
    (
        SELECT 
            emp_id,
            SUM(service_end_time - service_start_time) AS service_duration

        FROM 
            data 

        GROUP BY 
            emp_id 
    ) a

    JOIN
    (
        SELECT 
            emp_id, 
            SUM(available_end_time - available_start_time) AS available_duration

        FROM 
            data 

        GROUP BY
            emp_id
    ) b 
    ON a.emp_id = b.emp_id 

GROUP BY
    a.emp_id
于 2013-03-01T13:19:08.313 に答える