-1

PHP の mysqli 拡張機能を使用して、LIKE クエリの準備済みステートメントを作成しようとしています。しかし、何を試しても、常に次のエラーが発生します。

Fatal error: Problem preparing query (SELECT f.*,r.slug FROM `foods` AS f INNER JOIN `resturants` AS r ON f.`rest_id` = r.`rest_id` WHERE f.`name` LIKE CONCAT('%',"f", '%')) You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''%',"f", '%')' at line 4 in /path/to/class.mysqli.php on line 462

次のクエリを試してみましたが、役に立ちませんでした:
($s検索対象の文字列になります。)

SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE '%?%'

SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE CONCAT('%', ?, '%')


SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE CONCAT('%', {$s}, '%')


SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE '%{$s}%'

平：

sprintf("SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE '%%%s%%'", $s)

助けてください、私はイライラしています。

4

2 に答える 2

4

LIKE の後に式を変数に移動します。

$param = '%somestring%';

$sql = "SELECT f.*,r.slug FROM `foods` AS f
INNER JOIN `resturants` AS r
ON f.`rest_id` = r.`rest_id`
WHERE f.`name` LIKE ?"

アップデート：

多分これが役立つでしょう

-- test.sql
CREATE TABLE supportContacts (
     id int auto_increment primary key, 
     type varchar(20), 
     details varchar(30)
);

INSERT INTO supportContacts
(type, details)
VALUES
('Email', 'admin@sqlfiddle.com'),
('Twitter', '@sqlfiddle');

<?php
// test.php
$mysqli = new mysqli("localhost", "root", "root", "test");
$sql = 'SELECT type FROM supportContacts WHERE type LIKE ?'; // here is only ?, no %

$stmt = $mysqli->prepare($sql);
$type = 'E%'; // and here you can put % sign
$stmt->bind_param('s', $type);
$stmt->execute();
$stmt->bind_result($result);
$stmt->fetch();
var_dump($result);
于 2013-03-05T17:32:12.840 に答える
0

も引用符で囲む%必要があります。

于 2013-03-05T17:09:36.637 に答える