すべての連絡先の電話番号をArrayListに保存しようとしていますが、方法がわかりません。ContactsContractで1つずつ選択する代わりにそれらを取得する方法はありますか?
質問する
46486 次
7 に答える
46
ContentResolver cr = mContext.getContentResolver(); //Activity/Application android.content.Context
Cursor cursor = cr.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
if(cursor.moveToFirst())
{
ArrayList<String> alContacts = new ArrayList<String>();
do
{
String id = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
if(Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0)
{
Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?",new String[]{ id }, null);
while (pCur.moveToNext())
{
String contactNumber = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
alContacts.add(contactNumber);
break;
}
pCur.close();
}
} while (cursor.moveToNext()) ;
}
于 2013-03-06T09:29:22.780 に答える
19
これを試して:
Cursor managedCursor = getContentResolver()
.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
new String[] {Phone._ID, Phone.DISPLAY_NAME, Phone.NUMBER}, null, null, Phone.DISPLAY_NAME + " ASC");
また、カーソルを移動することで、このすべてのデータを任意のデータ構造に格納できます。
于 2013-03-06T09:29:48.717 に答える
7
このコードは、連絡先ごとに追加のクエリを作成しないため、回答のコードよりもはるかに高速に機能します。
private static final String CONTACT_ID = ContactsContract.Contacts._ID;
private static final String HAS_PHONE_NUMBER = ContactsContract.Contacts.HAS_PHONE_NUMBER;
private static final String PHONE_NUMBER = ContactsContract.CommonDataKinds.Phone.NUMBER;
private static final String PHONE_CONTACT_ID = ContactsContract.CommonDataKinds.Phone.CONTACT_ID;
public static ArrayList<String> getAll(Context context) {
ContentResolver cr = context.getContentResolver();
Cursor pCur = cr.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
new String[]{PHONE_NUMBER, PHONE_CONTACT_ID},
null,
null,
null
);
if(pCur != null){
if(pCur.getCount() > 0) {
HashMap<Integer, ArrayList<String>> phones = new HashMap<>();
while (pCur.moveToNext()) {
Integer contactId = pCur.getInt(pCur.getColumnIndex(PHONE_CONTACT_ID));
ArrayList<String> curPhones = new ArrayList<>();
if (phones.containsKey(contactId)) {
curPhones = phones.get(contactId);
}
curPhones.add(pCur.getString(pCur.getColumnIndex(PHONE_NUMBER)));
phones.put(contactId, curPhones);
}
Cursor cur = cr.query(
ContactsContract.Contacts.CONTENT_URI,
new String[]{CONTACT_ID, HAS_PHONE_NUMBER},
HAS_PHONE_NUMBER + " > 0",
null,null);
if (cur != null) {
if (cur.getCount() > 0) {
ArrayList<String> contacts = new ArrayList<>();
while (cur.moveToNext()) {
int id = cur.getInt(cur.getColumnIndex(CONTACT_ID));
if(phones.containsKey(id)) {
contacts.addAll(phones.get(id));
}
}
return contacts;
}
cur.close();
}
}
pCur.close();
}
return null;
}
于 2016-08-02T10:26:39.333 に答える
1
これも試して、すべての連絡先を取得してください。
Cursor cursor = context.getContentResolver().query(Phone.CONTENT_URI, null , null , null,
"upper("+Phone.DISPLAY_NAME + ") ASC");
于 2014-08-23T13:58:57.143 に答える
1
kotlinでこれを試してすべての連絡先を取得する
fun getContacts(ctx: Context): List<ContactModel>? {
val list: MutableList<ContactModel> = ArrayList()
val contentResolver = ctx.contentResolver
val cursor: Cursor? =
contentResolver.query(
ContactsContract.Contacts.CONTENT_URI, null,
null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC"
)
if (cursor!!.count > 0) {
while (cursor.moveToNext()) {
val id =
cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID))
if (cursor.getInt(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
val cursorInfo: Cursor? = contentResolver.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
arrayOf(id),
null
)
val inputStream: InputStream? =
ContactsContract.Contacts.openContactPhotoInputStream(
ctx.contentResolver,
ContentUris.withAppendedId(
ContactsContract.Contacts.CONTENT_URI,
id.toLong()
)
)
val person: Uri =
ContentUris.withAppendedId(
ContactsContract.Contacts.CONTENT_URI,
id.toLong()
)
val pURI: Uri = Uri.withAppendedPath(
person,
ContactsContract.Contacts.Photo.CONTENT_DIRECTORY
)
var photo: Bitmap? = null
if (inputStream != null) {
photo = BitmapFactory.decodeStream(inputStream)
}
while (cursorInfo!!.moveToNext()) {
val info = ContactModel()
info.setId(id)
info.setName(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)))
info.setMobileNumber(
cursorInfo.getString(
cursorInfo.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.NUMBER
)
)
)
photo?.let { info.setPhoto(it) }
info.setPhotoURI(pURI)
list.add(info)
}
cursorInfo.close()
}
}
cursor.close()
}
return list
}
このために1つのデータクラスを作成する必要があります
class ContactModel {
@SerializedName("id")
private var id: String = ""
@SerializedName("name")
private var name: String? = ""
@SerializedName("mobileNumber")
private var mobileNumber: String? = ""
@SerializedName("photo")
private var photo: Bitmap? = null
@SerializedName("photoURI")
private var photoURI: Uri? = null
fun getId(): String {
return id
}
fun setId(id: String) {
this.id = id
}
fun getName(): String? {
return name
}
fun setName(name: String) {
this.name = name
}
fun getMobileNumber(): String? {
return mobileNumber
}
fun setMobileNumber(mobileNumber: String) {
this.mobileNumber = mobileNumber
}
fun getPhoto(): Bitmap? {
return photo
}
fun setPhoto(photo: Bitmap) {
this.photo = photo
}
fun getPhotoURI(): Uri? {
return photoURI
}
fun setPhotoURI(photoURI: Uri) {
this.photoURI = photoURI
}
override fun toString(): String {
return "ContactModel(id='$id', name=$name, mobileNumber=$mobileNumber, photo=$photo, photoURI=$photoURI)"
}
}
于 2020-09-08T13:43:06.297 に答える
0
この方法は最適化されており、個別の連絡先のみを取得します
@RequiresApi(api = Build.VERSION_CODES.N)
private List<ModelContacts> getContacts() {
ArrayList<ModelContacts> list = new ArrayList<>();
Cursor cursor = this.getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
cursor.moveToFirst();
while (cursor.moveToNext()) {
list.add(new ModelContacts(cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
, cursor.getString(cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER))));
}
cursor.close();
if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
List<ModelContacts> distinctList = list.stream().filter(distinctByKey(c -> c.getName()))
.collect(Collectors.toList());
return distinctList;
}
else {
return list;
}
}
@RequiresApi(api = Build.VERSION_CODES.N)
public static <T> Predicate<T> distinctByKey (final Function<? super T, Object> keyExtractor)
{
Map<Object, Boolean> map = new ConcurrentHashMap<>();
return t -> map.putIfAbsent(keyExtractor.apply(t), Boolean.TRUE) == null;
}
于 2020-09-18T11:37:42.303 に答える
0
まず、連絡先データを保存するためのモデルクラスを作成します。連絡先にgetAllContact(context)メソッドを追加します。マニフェストに連絡先の読み取りのユーザー権限を追加することを忘れないでください。
data class ContactModel(
var name: String? = "",
var mobileNumber: String? = "",
var photoURI: Uri? = null
)
class ContactsFragment : Fragment(R.layout.contacts_fragment) {
private var _binding: ContactsFragmentBinding? = null
private val binding get() = _binding
override fun onCreateView(
inflater: LayoutInflater,
container: ViewGroup?,
savedInstanceState: Bundle?
): View? {
_binding = ContactsFragmentBinding.inflate(inflater, container, false)
return binding?.root
}
@SuppressLint("Recycle")
override fun onViewCreated(view: View, savedInstanceState: Bundle?) {
super.onViewCreated(view, savedInstanceState)
if (!context?.let { checkIfAlreadyHavePermission(it) }!!) {
context?.let { requestContactPermission(it) }
} else {
lifecycleScope.launch(Dispatchers.IO) {
context?.let { getAllContacts(it) }
Log.e("con", "con" + getAllContacts(requireContext()))
}
}
}
fun getAllContacts(context: Context): List<ContactModel> {
val contactList: ArrayList<ContactModel> = ArrayList()
val contentResolver = context.contentResolver
val notifier: Cursor? = contentResolver.query(ContactsContract.Contacts.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC")
if (notifier!!.count > 0) {
while (notifier.moveToNext()) {
val id = notifier.getString(notifier.getColumnIndex(ContactsContract.Contacts._ID))
if (notifier.getInt(notifier.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0)
{ val notifierInfo: Cursor? = contentResolver.query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?", arrayOf(id), null
)
val user: Uri =
ContentUris.withAppendedId(
ContactsContract.Contacts.CONTENT_URI,
id.toLong()
)
val userURI: Uri = Uri.withAppendedPath(
user,
ContactsContract.Contacts.Photo.CONTENT_DIRECTORY
)
while (notifierInfo!!.moveToNext()) {
val info = ContactModel()
info.name =
(notifier.getString(notifier.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)))
info.mobileNumber = (
notifierInfo.getString(
notifierInfo.getColumnIndex(
ContactsContract.CommonDataKinds.Phone.NUMBER
)
)
)
contactList.add(info)
}
notifierInfo.close()
}
}
notifier.close()
}
return contactList
}
于 2021-02-06T08:55:51.047 に答える