8

単純なテーブルがあり、XML に変換する必要があります

 Declare @Person TABLE
(   [BusinessEntityID] [int] NOT NULL,
    [PersonType] [varchar](2) NULL,
    [Title] [varchar](30) NULL,
    [FirstName] [varchar](30) NULL,
    [MiddleName] [varchar](30) NULL,
    [LastName] [varchar](30) NULL)

Insert Into @Person Values(10001,'IN','Article','Carolyn','Jo','Alonso')

SQL Server の For XML で出力するには、この xml が必要です。

<?xml-stylesheet type='text/xsl' href='result.xsl'?>
<documents>
  <document>
    <field name="BusinessEntityID">10001</field>
    <field name="PersonType">IN</field>
    <field name="Title">Article</field>
    <field name="FirstName">Carolyn</field>
    <field name="MiddleName">Jo</field>
    <field name="LastName">Alonso</field>
  </document>
 </documents>
4

1 に答える 1

8

次のXMLPATHクエリは、ほとんどの方法で使用できるはずです。スタイルシートヘッダーを追加するだけです。

SELECT 
'BusinessEntityID' AS 'document/field/@name'
,   BusinessEntityID AS 'document/field'
,   '' AS 'document'
,   'documentType' AS 'document/field/@name'
,   PersonType AS 'document/field'
,   '' AS 'document'
,   'Title' AS 'document/field/@name'
,   Title AS 'document/field'
,   '' AS 'document'
,   'FirstName' AS 'document/field/@name'
,   FirstName AS 'document/field'
,   '' AS 'document'
,   'MiddleName' AS 'document/field/@name'
,   MiddleName AS 'document/field'
,   '' AS 'document'
,   'LastName' AS 'document/field/@name'
,   LastName AS 'document/field'
,   '' AS 'document'
FROM @Person
FOR XML PATH(''), ROOT('documents')
于 2013-03-07T08:54:18.380 に答える