0

私は次の表を持っています：

CREATE TABLE `document` (
    `id` INT(10) NOT NULL AUTO_INCREMENT,
    `systemReceivedTime` BIGINT(20) NOT NULL DEFAULT '0',
    `finishTime` BIGINT(20) NOT NULL DEFAULT '0',
    PRIMARY KEY (`id`)
)

行：

systemReceivedTime 1360747818002 // > 2013-02-13 11:30:18
finishTime         1362995961805 // > 2013-03-11 11:59:22

私が必要としているのは、2つの日付の間の就業日数を計算する方法です。

日付を正しく表示するには、次の選択を使用します。

from_unixtime(systemreceivedtime/1000) ,
if(finishtime=0,null,from_unixtime(finishtime/1000))
4

2 に答える 2

0 
SELECT 5 * (DATEDIFF(FROM_UNIXTIME(finishTime/1000), FROM_UNIXTIME(systemReceivedTime/1000)) DIV 7) + MID('0123455501234445012333450122234501101234000123450', 7 * WEEKDAY(FROM_UNIXTIME(systemReceivedTime/1000)) + WEEKDAY(FROM_UNIXTIME(finishTime/1000)) + 1, 1)x FROM document;
于 2013-03-11T13:20:15.773 に答える
0

私は変数を使った解決策を持っています。morの数式を一緒に使用することもできますが、このように読みやすくなると思います。

SELECT
    calc.id,
    calc.work_dates
FROM
    (
        SELECT
            d.id,
            @from :=from_unixtime(d.systemreceivedtime/1000)        AS dfrom,
            @to := from_unixtime(d.finishtime/1000)                 AS dto,
            -- Caclulate the Diffrent between both dates
            @ddiff := DATEDIFF(@to, @from)          AS ddiff,
            -- get the weekday of the startdate
            @wd := WEEKDAY(@from)                       AS weekdays,
            -- calculate how many days are from start of week until enddate
            @d1 := @ddiff + @wd                         AS days_from_week_start,
            -- calculate how many full week this is
            @fullweeks := @d1 DIV 7                     AS full_weeeks,
            -- calculate how many workdays are not in a fullweek
            @restdays := LEAST(MOD(@d1, 7), 5)      As rest_working_days,
            -- Weeks * 5 Workdays + rest_workdays - days_from_week_start
            @fullweeks * 5 + @restdays - @wd            AS work_dates
        FROM
            document AS d
    ) AS calc
于 2013-03-11T14:09:01.403 に答える