EditText を 2 文字と 5 桁の数字で構成してください。正規表現を使おうと思ったのですが、使い方がわかりません。前もって感謝します
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99 次
2 に答える
0
boolean validate(String str){
int letters = 0;
int numbers = 0;
int others = 0;
for(int i=0; i<str.length(); i++){
char ch = str.getAt(i);
if(Character.isLetter(ch)){
letters++;
}
else if (Character.isDigit(ch)){
numbers++;
}
else{
others++;
}
}
return others == 0 && numbers==5 && letters == 2;
}
于 2013-03-13T18:40:06.250 に答える
0
EditText edit = (EditText) this.findViewById(R.id.edit_text);
edit.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence s, int start,
int before, int count) {
char[] c_arr = s.toCharArray();
int letterCount=0;
int digitCount=0;
for(Character c : c_arr){
try{
Integer.parseInt(c.toString())
digitCount++;
if(digitCount > 2){
// alert here
s = s.substring(0, s.length() - 1);
EditText edit = (EditText) this.findViewById(R.id.edit_text);
edit.setText(s);
break;
}
}catch (NumberFormatException e) {
letterCount++;
if(letterCount > 5){
// alert here
s = s.substring(0, s.length() - 1);
EditText edit = (EditText) this.findViewById(R.id.edit_text);
edit.setText(s);
break;
}
}
}
}
@Override
public void beforeTextChanged(CharSequence s, int start,
int count, int after) {}
@Override
public void afterTextChanged(Editable s) {
}
});
于 2013-03-13T18:46:35.370 に答える