3

joinON句を使用して「IN」ステートメントを追加するまでのこれまでのすべての結果の取得

私のコードは次のようなものです：

// $this->table = 'category';
$sql = $this->getSql();
$select = $sql->select();
$select->join('user_category_subscriptions', 'user_category_subscriptions.category_id = category.id AND user_category_subscriptions.status IN (1,2,3,4)', array(), 'left');
$select->where(array('category.user_id = 2 OR (user_category_subscriptions.status IN (2,4))'));

エラー

ZEND\DB\ADAPTER\EXCEPTION\INVALIDQUERYEXCEPTION
File:E:\htdocs\myproj\vendor\zendframework\zendframework\library\Zend\Db\Adapter\Driver\Pdo\Statement.php:245
Message:Statement could not be executed

使用'echo$ select-> getSqlString（）;' クエリを出力するには：

SELECT "categories".* FROM "categories" 
LEFT JOIN "user_category_subscriptions" 
ON "user_category_subscriptions"."category_id" = "categories"."category_id" AND "user_category_subscriptions"."status" IN ("1""," "2""," "3""," "4")
WHERE category.user_id = 2 OR (user_category_subscriptions.status IN (2,4))

したがって、問題はzendが（1,2,3,4）を（ "1" "、" "2" "、" "3" "、" "4"）に自動変換することです。

これを解決するためのアイデアはありますか？ありがとう

4

2 に答える 2

6

I think you can pass an expression instead of the join string:

// $this->table = 'category';
$sql = $this->getSql();
$select = $sql->select();

$join = new Expression('user_category_subscriptions.category_id = category.id AND user_category_subscriptions.status IN (1,2,3,4)');

$select->join('user_category_subscriptions', $join, array(), 'left');
$select->where(array('category.user_id = 2 OR (user_category_subscriptions.status IN (2,4))'));
于 2013-03-14T09:12:11.880 に答える
2

これを試して

$select->where
       ->AND->NEST->equalTo('category.user_id', 2)
       ->addPredicate(new Sql\Predicate\In('user_category_subscriptions.status', array(2,4)));
于 2013-03-14T05:44:03.363 に答える