SQL列からすべての行をエコーする必要があります。
これが私のPHPです
$query2="SELECT * FROM field_activity WHERE field_id='$fetch'";
$result2 = mysql_query($query2);
while($row = mysql_fetch_array($result2)){
$activity = $row['activity'];
$cr_date = date_create($row['date']);
$for_date = date_format($cr_date, 'F j, Y');
$amount = $row['amount'];
$acres_complete = $row['acres_complete'];
$duration = $row['duration'];
$status = $row['status'];
}
これが私のHTML出力です。
<?php
{
echo "<tr>";
echo "<td width='16%'><strong>Date</strong></td>";
echo "<td width='16%'>$for_date</td>";
echo "</tr><tr>";
echo "<td width='16%'><strong>Activity</strong></td>";
echo "<td width='16%'>$activity</td>";
echo "</tr><tr>";
echo "<td width='16%'><strong>Amount</strong></td>";
echo "<td width='16%'>$amount</td>";
echo "</tr><tr>";
echo "<td width='16%'><strong>Acres Complete</strong></td>";
echo "<td width='16%'>$acres_complete</td>";
echo "</tr><tr>";
echo "<td width='16%'><strong>Duration</strong></td>";
echo "<td width='16%'>$duration</td>";
echo "</tr><tr>";
echo "<td width='16%'><strong>Status</strong></td>";
echo "<td width='16%'>$status</td>";
echo "</tr>";
}
?>
これは、列の1つの行(最新の行)のみを表示します。すべての行を表示したいのですが。