数時間前に問題を投稿しましたが、よりわかりやすい方法で質問する方法を見つけたと思います。
これは私のコードです:
// 1. Intro
var introPL1:Array = ["intro1","intro2","intro3","intro4"];
var introPL2:Array = ["intro5","intro6","intro7","intro8","intro9"];
var introPL3:Array = ["intro10","intro11"];
var introPL4:Array = ["intro12","intro13"];
var allIntro:Array = [introPL1,introPL2,introPL3,introPL4];
// 2. Clothes
var clothesPL1:Array = ["clothes1","clothes2","clothes3","clothes4","clothes5"];
var clothesPL2:Array = ["clothes6","clothes7","clothes8"];
var clothesPL3:Array = ["clothes9","clothes10"];
var clothesPL4:Array = ["clothes11","clothes12","clothes13"];
var allClothes:Array = [clothesPL1,clothesPL2,clothesPL3,clothesPL4];
// 3. Colored Numbers
var colNumPL1:Array = ["colNum1","colNum2","colNum3","colNum4","colNum5"];
var colNumPL2:Array = ["colNum6","colNum7","colNum8"];
var colNumPL3:Array = ["colNum9","colNum10"];
var colNumPL4:Array = ["colNum11","colNum12","colNum13"];
var allColNum:Array = [colNumPL1,colNumPL2,colNumPL3,colNumPL4];
var allStuff:Array;
allStuff = allIntro.concat(allClothes, allColNum);
trace(allStuff[4]);
allStuff[4] をトレースすると、「clothes1,clothes2,clothes3,clothes4,clothes5」と表示されます。問題は、すべてのものを allStuff 配列 (サブ配列なし) に入れ、allStuff[4] をトレースするときに "intro5" (巨大な allStuff 配列の 5 番目の項目) を表示することです。 .