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フォームにパスワードを入力するための次のスクリプトがあります。

$('#genPass').click(function() {
    var password = "";
    var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";

    for (var i = 0; i < 12; i++)
    password += possible.charAt(Math.floor(Math.random() * possible.length));
    $('input[name="password"]').val(password);
    document.getElementById("str").innerHTML = password;


});

function passwordStrength(password)

{

    var desc = new Array();

    desc[0] = "Very Weak";

    desc[1] = "Weak";

    desc[2] = "Better";

    desc[3] = "Medium";

    desc[4] = "Strong";

    desc[5] = "Strongest";



    var score   = 0;



    //if password bigger than 6 give 1 point

    if (password.length > 6) score++;



    //if password has both lower and uppercase characters give 1 point      

    if ( ( password.match(/[a-z]/) ) && ( password.match(/[A-Z]/) ) ) score++;



    //if password has at least one number give 1 point

    if (password.match(/\d+/)) score++;



    //if password has at least one special caracther give 1 point

    if ( password.match(/.[!,@,#,$,%,^,&,*,?,_,~,-,(,)]/) ) score++;



    //if password bigger than 12 give another 1 point

    if (password.length > 12) score++;



     document.getElementById("passwordStrength").innerHTML = desc[score];

     document.getElementById("passwordStrength").className = "strength" + score;


}

フィールドを入力し、パスワードボタンを生成します：

<input name="password" type="password" size="25" maxlength="20" id="pass" onchange="passwordStrength(this.value)" onselect="passwordStrength(this.value)" onclick="passwordStrength(this.value)"/>


<button id="genPass" type="button">Generate Password !</button>

これで、ボタンをクリックするとパスワード入力にパスワードが生成されますが、パスワード入力フィールドをクリックすると、パス強度が表示されます。生成ボタンをクリックすると強さを発揮したいのですが、何かアイデアはありますか？

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1 に答える 1

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$('#genPass').click(function() {
    var password = "";
    var possible = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";

    for (var i = 0; i < 12; i++)
    password += possible.charAt(Math.floor(Math.random() * possible.length));
    $('input[name="password"]').val(password);
    document.getElementById("str").innerHTML = password;
    passwordStrength(password); //added this

});
于 2013-03-24T09:45:57.337 に答える