これは私のfqlです:
$fql = "SELECT uid, name, online_presence, status
FROM user
WHERE uid IN ( SELECT uid2 FROM friend WHERE uid1 = '".$user_id."') ";
値はonline_presence
常に を返しnull
ます。
これは私のfqlです:
$fql = "SELECT uid, name, online_presence, status
FROM user
WHERE uid IN ( SELECT uid2 FROM friend WHERE uid1 = '".$user_id."') ";
値はonline_presence
常に を返しnull
ます。