これらの値のいずれかを持つデータフレームがあります。
from=c("A","C","G","T","R","Y","M","K","W", "S","N")
それに応じて置き換えたい
to=c("AA","CC","GG","TT","AG","CT","AC","GT","AT", "CG","NN")
それを行う最良の方法は何ですか?すべての値をループして置き換えますか? またはマトリックス位置をループします。または他の解決策はありますか?
dd<-matrix(sample(from, 100, replace=TRUE), 10)
dd
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,] "K" "S" "G" "T" "R" "N" "A" "C" "W" "M"
[2,] "Y" "K" "S" "G" "T" "R" "N" "A" "C" "W"
[3,] "M" "Y" "K" "S" "G" "T" "R" "N" "A" "C"
[4,] "W" "M" "Y" "K" "S" "G" "T" "R" "N" "A"
[5,] "C" "W" "M" "Y" "K" "S" "G" "T" "R" "N"
[6,] "A" "C" "W" "M" "Y" "K" "S" "G" "T" "R"
[7,] "N" "A" "C" "W" "M" "Y" "K" "S" "G" "T"
[8,] "R" "N" "A" "C" "W" "M" "Y" "K" "S" "G"
[9,] "T" "R" "N" "A" "C" "W" "M" "Y" "K" "S"
[10,] "G" "T" "R" "N" "A" "C" "W" "M" "Y" "K"
to to to のすべてでループを使用しました。
myfunc<-function(xx){
from=c("A","C","G","T","R","Y","M","K","W", "S","N");
to=c("AA","CC","GG","TT","AG","CT","AC","GT","AT", "CG","NN");
for (i in 1:11){
xx[xx==from[i]]<-to[i];
}
return(xx);
}
小さなマトリックスではうまくいきましたが、大きなマトリックスでは時間がかかります。効率的な解決策はありますか?
ありがとう