0 
String = "Mod1:10022932,10828075,5946410,13321905,5491120,5030731|Mod2:22704455,22991440,22991464,21984312,21777721,21777723,21889761,21939852,23091478,22339903,23091485,22099714,21998260,22364832,21939858,21944274,21944226,22800221,22704443,21777728,21777719,21678184,21998265,21834900,21984331,22704454,21998261,21944214,21862610,21836482|Mod3:10828075,13321905,5491120,5946410,5030731,15806212,4100566,4787137,2625339,2408317,2646868,19612047,2646862,11983534,8591489,19612048,10249319,14220471,15806209,13330887,15075124,17656842,3056657,5086273|Mod4:10828075,5946410,13321905,5030731,5491120,4787137,4100566,15806212,2625339,3542205,2408317,2646862,2646868|Mod5:10022932;0.2512,10828075;0.2093,5030731;0.1465,5946410;0.1465,4787137;0.1465,2625339;0.0143,5491120;0.0143,13321905;0.0143,3542205;0.0143,15806212;0.0119,4100566;0.0119,19612047;0.0100,2408317;0.0100"

各タイトル (Mod1、Mod2 ..) と各タイトルに属する ID を取得できるように分割するにはどうすればよいですか。

これは私がこれまでに試したもので、パイプの後のすべてを削除していますが、これは望ましくありません。

mod_name = string.split(":")[0]
mod_ids = string.split(":")[1] #This gets me the ID's but also include the |Mod*
ids = mod_mod_ids.split("|").first.strip #Only returns Id's before the first "|"

望ましい出力: mod_name と mod_ids をそれぞれの列に保存する必要があります。

mod_name = #name ("Mod1...Mod2 etc) #string
mod_ids = #ids (All Ids after the ":" in Mod*:) #array
4

5 に答える 5

1

タイトルから簡単にアクセスできるように結果としてハッシュが必要な場合は、次のようにします。

 str.split('|').inject({}){|h,x| k,v = x.split(':'); h[k] = v.split(','); h}

  => {
      "Mod1"=>["10022932", "10828075", "5946410", "13321905", "5491120", "5030731"], 
      "Mod2"=>["22704455", "22991440", "22991464", "21984312", "21777721", "21777723", "21889761", "21939852", "23091478", "22339903", "23091485", "22099714", "21998260", "22364832", "21939858", "21944274", "21944226", "22800221", "22704443", "21777728", "21777719", "21678184", "21998265", "21834900", "21984331", "22704454", "21998261", "21944214", "21862610", "21836482"], 
      "Mod3"=>["10828075", "13321905", "5491120", "5946410", "5030731", "15806212", "4100566", "4787137", "2625339", "2408317", "2646868", "19612047", "2646862", "11983534", "8591489", "19612048", "10249319", "14220471", "15806209", "13330887", "15075124", "17656842", "3056657", "5086273"], 
      "Mod4"=>["10828075", "5946410", "13321905", "5030731", "5491120", "4787137", "4100566", "15806212", "2625339", "3542205", "2408317", "2646862", "2646868"], 
      "Mod5"=>["10022932;0.2512", "10828075;0.2093", "5030731;0.1465", "5946410;0.1465", "4787137;0.1465", "2625339;0.0143", "5491120;0.0143", "13321905;0.0143", "3542205;0.0143", "15806212;0.0119", "4100566;0.0119", "19612047;0.0100", "2408317;0.0100"]
     }
于 2013-04-17T19:12:29.337 に答える
0

@tillerjsのヘルプのおかげで、私が最終的に使用したもの。

data = sting.split("|")
data.each do |mod|
   module_name = mod.split(":")[0]
   recommendations = mod.split(":")[1]
end
于 2013-04-17T18:08:44.757 に答える