4

私がタグ付けされた特定の友人の写真と、この同じ友人がタグ付けされた私の写真を取得したい.友達リスト:

$facebook_login = "0";
$user = $facebook->getUser();
$perms = array('scope' => 'email,user_photos,read_mailbox');

if ($user) {
  try {
    $user_profile = $facebook->api('/me');
$facebook_login = "1";
  } catch (FacebookApiException $e) {
    $user = null;
  }

} else {
    die('<script>top.location.href="'.$facebook->getLoginUrl($perms).'";</script>');
}



//friend photos that I'm tagged in
$query = "SELECT id FROM photo WHERE from = $_POST[friend_id] AND tags IN ($user)";
$result = $facebook->api(array(
  'method' => 'fql.query',
  'query' => $query,
));

echo sprintf('<pre>%s</pre>', print_r($result,TRUE));


//my photos with my friend tagged in
$query = "SELECT id FROM photo WHERE from = $user AND tags IN ($_POST[friend_id])";
$result = $facebook->api(array(
  'method' => 'fql.query',
  'query' => $query,
));

echo sprintf('<pre>%s</pre>', print_r($result,TRUE));

これはできますか？

ありがとう

4

1 に答える 1

2

次のクエリを試してください。

あなたがタグ付けされた友人の写真を取得するには:

$friend_id = $_POST['friend_id'];
$query = "SELECT object_id 
          FROM photo 
          WHERE owner=$friend_id AND 
                object_id IN (SELECT object_id FROM photo_tag WHERE subject=me())";

友達がタグ付けされたあなたの写真:

$query = "SELECT object_id 
          FROM photo 
          WHERE owner=me() AND 
                object_id IN (SELECT object_id FROM photo_tag WHERE subject=$friend_id)";
于 2013-05-09T00:09:39.060 に答える