このネストされた実行ループを COBOL で実行できないのはなぜですか?
END-PERFORMを入れると。EXIT PROGRAM の直前にある最後の行よりも早く、どの行でも動作します。しかし、毎回 INPUT C 値を表示するプログラムが必要です。外側の実行ループで。それは私を夢中にさせます。
PROCEDURE DIVISION USING INPUTC CIPHER.
COMPUTE CIPHERMAX = CIPHER.
MULTIPLY -1 BY CIPHER
---> PERFORM VARYING CIPHER FROM 0 BY 1
UNTIL CIPHERMAX = CIPHER
DISPLAY 'This is loop number: ' CIPHER
INSPECT INPUTC CONVERTING
"avcdefghijklmnopqrstuvwxyz" to "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
COMPUTE CONVERTNUM = FUNCTION MOD (CIPHER, 26)
INSPECT FUNCTION REVERSE(INPUTC) TALLYING LENGTHNUM FOR LEADING SPACES
COMPUTE LENGTHNUM = LENGTH OF CIPHER - LENGTHNUM
---> PERFORM UNTIL SENTRY = LENGTHNUM
IF ((FUNCTION ORD(INPUTC(SENTRY:1)) + CONVERTNUM) > (FUNCTION ORD('Z')))
MOVE FUNCTION CHAR((FUNCTION ORD(INPUTC(SENTRY:1)) + CONVERTNUM) - 26) TO RECHAR
ELSE
MOVE FUNCTION CHAR(FUNCTION ORD(INPUTC(SENTRY:1)) + CONVERTNUM) TO RECHAR
END-IF
IF (((FUNCTION ORD(INPUTC(SENTRY:1))) >= (FUNCTION ORD('A'))) AND
((FUNCTION ORD(INPUTC(SENTRY:1))) <= (FUNCTION ORD('Z'))))
IF ((FUNCTION ORD(INPUTC(SENTRY:1)) + CONVERTNUM) > (FUNCTION ORD('Z')))
INSPECT INPUTC(SENTRY:1) REPLACING ALL INPUTC(SENTRY:1) BY RECHAR
ELSE
INSPECT INPUTC(SENTRY:1) REPLACING ALL INPUTC(SENTRY:1) BY RECHAR
END-IF
ELSE
INSPECT INPUTC(SENTRY:1) REPLACING ALL INPUTC(SENTRY:1) BY INPUTC(SENTRY:1)
END-IF
COMPUTE SENTRY = SENTRY + 1
---> END-PERFORM
DISPLAY INPUTC.
COMPUTE LOOPI = LOOPI + 1
--->END-PERFORM.
EXIT PROGRAM.
END PROGRAM SOLVE.