3

グループ化された値に基づいて、あるテーブル dbo.VTM_duedate からグループ化された値 (列: 'Criticality') を取得し、別のテーブル dbo.TPM_scan で次のカウント値 (列: 'DEVICE_NAME') を取得したいと考えています。

表1

USE tempdb;
GO

IF OBJECT_ID('dbo.VTM_duedate') IS NOT NULL
DROP TABLE dbo.VTM_duedate;
GO

CREATE TABLE dbo.VTM_duedate
(
Criticality   varchar(30) NOT NULL,
KB        varchar(10) NOT NULL
);

INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Medium', 157848);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('High', 155439);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('High', 635533);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Critical', 189164);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('High', 188641);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Critical', 537990);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Critical', 1349605);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Critical', 5646789);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Medium', 6545789);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('High', 5637965);
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Medium', 6464367) ;
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Medium', 1323123) ;
INSERT INTO dbo.VTM_duedate(Criticality, KB)
VALUES('Medium', 1004326) ;
GO

表 2

USE tempdb;
GO

IF OBJECT_ID('dbo.TPM_scan') IS NOT NULL
DROP TABLE dbo.TPM_scan;
GO

CREATE TABLE dbo.TPM_scan
(
DEVICE_NAME   varchar(30) NOT NULL,
APP_ID        varchar(10) NOT NULL,
Criticality   varchar(10) NOT NULL
);

INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('LDNSQLF700', 157848, 'Medium');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('LDNSQLF700', 155439, 'High');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('LDNSQLF700', 635533, 'High');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('NYSQL502', 189164, 'Critical');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('NYSQL502', 188641, 'High');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('AUSSQL140', 537990, 'High');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('AUSSQL140', 1349605, 'Critical');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('JAP543X2', 5646789, 'Medium');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('EU456CLX', 6545789, 'Critical');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('EUCTX654', 5637965, 'High');
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('EUCTX654', 6464367, 'Medium') ;
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('EUCTX654', 1323123, 'High') ;
INSERT INTO dbo.TPM_scan(DEVICE_NAME, APP_ID, Criticality)
VALUES('EUCTX654', 1004326, 'Medium') ;
GO

予想された結果：

Criticality   Device_count
 Critical           3
 High               6
 Medium             4
4

2 に答える 2

1

これは、SQLFiddle でスキーマを作成したときに答えが得られたようです。 

SELECT COUNT(*) AS Device_Count, Criticality
FROM TPM_scan
GROUP BY criticality

http://www.sqlfiddle.com/#!6/c5287/6

于 2013-04-26T13:05:33.423 に答える