17

'blue'次の形式のテキストを含むのクラスを持つすべてのスパンを見つけるにはどうすればよいですか:

04/18/13 7:29pm

したがって、次のようになります。

04/18/13 7:29pm

また：

Posted on 04/18/13 7:29pm

これを行うためのロジックを構築するという点では、これは私がこれまでに得たものです: 

new_content = original_content.find_all('span', {'class' : 'blue'}) # using beautiful soup's find_all
pattern = re.compile('<span class=\"blue\">[data in the format 04/18/13 7:29pm]</span>') # using re
for _ in new_content:
    result = re.findall(pattern, _)
    print result

https://stackoverflow.com/a/7732827とhttps://stackoverflow.com/a/12229134を参照して、これを行う方法を見つけようとしましたが、これまでに得たのは上記だけです.

編集：

シナリオを明確にするために、次のスパンがあります。

<span class="blue">here is a lot of text that i don't need</span>

と

<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>

04/18/13 7:29pm残りのコンテンツは 必要ないことに注意してください。

編集2：

私も試しました：

pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
for _ in new_content:
    result = re.findall(pattern, _)
    print result

エラーが発生しました：

'TypeError: expected string or buffer'
4

3 に答える 3

27 
import re
from bs4 import BeautifulSoup

html_doc = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
</body>
</html>
"""

# parse the html
soup = BeautifulSoup(html_doc)

# find a list of all span elements
spans = soup.find_all('span', {'class' : 'blue'})

# create a list of lines corresponding to element texts
lines = [span.get_text() for span in spans]

# collect the dates from the list of lines using regex matching groups
found_dates = []
for line in lines:
    m = re.search(r'(\d{2}/\d{2}/\d{2} \d+:\d+[a|p]m)', line)
    if m:
        found_dates.append(m.group(1))

# print the dates we collected
for date in found_dates:
    print(date)

出力：

04/18/13 7:29pm
04/19/13 7:30pm
04/20/13 10:31pm
于 2013-04-27T06:04:19.347 に答える
4

これは、使用できる柔軟な正規表現です。

"(\d\d?/\d\d?/\d\d\d?\d?\s*\d\d?:\d\d[a|p|A|P][m|M])"

例：

>>> import re
>>> from bs4 import BeautifulSoup
>>> html = """
<html>
<body>
<span class="blue">here is a lot of text that i don't need</span>
<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>
<span class="blue">04/19/13 7:30pm</span>
<span class="blue">04/18/13 7:29pm</span>
<span class="blue">Posted on 15/18/2013 10:00AM</span>
<span class="blue">Posted on 04/20/13 10:31pm</span>
<span class="blue">Posted on 4/1/2013 17:09aM</span>
</body>
</html>
"""
>>> soup = BeautifulSoup(html)
>>> lines = [i.get_text() for i in soup.find_all('span', {'class' : 'blue'})]
>>> ok = [m.group(1)
      for line in lines
        for m in (re.search(r'(\d\d?/\d\d?/\d\d\d?\d?\s*\d\d?:\d\d[a|p|A|P][m|M])', line),)
          if m]
>>> ok
[u'04/18/13 7:29pm', u'04/19/13 7:30pm', u'04/18/13 7:29pm', u'15/18/2013 10:00AM', u'04/20/13 10:31pm', u'4/1/2013 17:09aM']
>>> for i in ok:
    print i

04/18/13 7:29pm
04/19/13 7:30pm
04/18/13 7:29pm
15/18/2013 10:00AM
04/20/13 10:31pm
4/1/2013 17:09aM
于 2013-04-27T05:57:26.783 に答える
2

このパターンは、あなたが探しているものを満たすようです:

>>> pattern = re.compile('<span class="blue">.*?(\d\d/\d\d/\d\d \d\d?:\d\d\w\w)</span>')
>>> pattern.match('<span class="blue">here is a lot of text that i dont need</span>')
>>> pattern.match('<span class="blue">this is the span i need because it contains 04/18/13 7:29pm</span>').groups()
('04/18/13 7:29pm',)
于 2013-04-27T05:46:12.340 に答える