ボタンクリックイベントで以下のコードから投稿データとリクエストヘッダーを取得できません..ここでは、URLと文字列を投稿データとして渡す必要があります...
ボタンをクリックすると、応答ヘッダー、要求ヘッダー、投稿データ、およびURLのコンテンツを取得する必要があります...しかし、以下のコードから要求ヘッダーと投稿データを取得できません...どこにあるか教えてもらえますか私は間違っている
private void button1_Click(object sender, EventArgs e)
{
try
{
string url = txtUrl.Text.Trim();
//HttpWebRequest WebRequestObject = (HttpWebRequest)WebRequest.Create(url);
// string result = null;
string postData = "This";
ASCIIEncoding ObjASCIIEncoding = new ASCIIEncoding();
byte[] fileData = ObjASCIIEncoding.GetBytes(postData);
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create(url);
// Set the Method property of the request to POST.
request.Method = "Post";
// Create POST data and convert it to a byte array.
WebHeaderCollection webh = request.Headers;
txtRequest.Text = webh.ToString();
// Set the ContentType property of the WebRequest.
request.ContentType = "application/x-wwww-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = fileData.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream();
// StreamReader r = new StreamReader(dataStream);
// string p = r.ReadToEnd();
// Write the data to the request stream.
dataStream.Write(fileData, 0, fileData.Length);
// Close the Stream object.
dataStream.Close();
//Get the response.
request.Credentials = CredentialCache.DefaultCredentials;
// HttpWebResponse Response = (HttpWebResponse)WebRequestObject.GetResponse();
WebResponse Response = request.GetResponse();
// HttpStatusCode code = Response.StatusCode;
//txtStatus.Text = code.ToString();
txtResponse.Text = Response.Headers.ToString();
// Open data stream:
Stream WebStream = Response.GetResponseStream();
// Create reader object:
StreamReader Reader = new StreamReader(WebStream);
// Read the entire stream content:
txtContent.Text = Reader.ReadToEnd();
// Cleanup
Reader.Close();
WebStream.Close();
Response.Close();
// var request = WebRequest.Create("http://www.livescore.com ");
//var response = request.GetResponse();
}
catch(Exception ex)
{
MessageBox.Show(ex.ToString());
}
}