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Spring と Hibernate を統合しようとしていますが、コードを実行して送信すると、この例外がスロー
org.springframework.dao.InvalidDataAccessResourceUsageException: could not insert: [com.xgrid.evaltask.Entities.User]; SQL [insert into User (UserName, passwd, ID) values (?, ?, ?)]; nested exception is org.hibernate.exception.SQLGrammarException: could not insert: [com.xgrid.evaltask.Entities.User]
されます Google で理由を見つけましたが、行き詰まり
ました どこが間違っているか教えてください
ここに applicationcontext.xml があります

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:aop="http://www.springframework.org/schema/aop" 
       xmlns:context="http://www.springframework.org/schema/context"
       xmlns:jee="http://www.springframework.org/schema/jee" 
       xmlns:tx="http://www.springframework.org/schema/tx"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
       xmlns:p="http://www.springframework.org/schema/p"
       xsi:schemaLocation="http://www.springframework.org/schema/aop 
    http://www.springframework.org/schema/aop/spring-aop-3.0.xsd 
    http://www.springframework.org/schema/context 
    http://www.springframework.org/schema/context/spring-context-3.0.xsd 
    http://www.springframework.org/schema/jee 
    http://www.springframework.org/schema/jee/spring-jee-3.0.xsd 
    http://www.springframework.org/schema/tx 
    http://www.springframework.org/schema/tx/spring-tx-3.0.xsd 
    http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd">

    <context:component-scan base-package="com.xgrid.evaltask"/>


    <bean id="dataSource"
             class="org.springframework.jdbc.datasource.DriverManagerDataSource"
             p:driverClassName="com.microsoft.sqlserver.jdbc.SQLServerDriver"
             p:url="jdbc:sqlserver://DBURL:1433;databaseName=Test_DB"
             p:username="sampleUser"
             p:password="@123456asdfgh" />


     <tx:annotation-driven transaction-manager="transactionManager" />


 <bean id="sessionFactory" class="org.springframework.orm.hibernate3.annotation.AnnotationSessionFactoryBean"
       p:dataSource-ref="dataSource"      
       p:packagesToScan="com.xgrid.evaltask"
       />

    <context:annotation-config />

    <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"
       p:sessionFactory-ref="sessionFactory" />

</beans>

ここに hibernate.cfg.xmlがあります
<hibernate-configuration> <session-factory> <property name="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</property> <!-- Enable this to see the SQL statements in the logs--> <property name="show_sql">true</property> <!-- This will drop our existing database and re-create a new one. Existing data will be deleted! --> <property name="hbm2ddl.auto">create</property> </session-factory> </hibernate-configuration>
これが私の DAO クラスです

@Repository("authorizeDao")
public class AuthorizeDaoImpl implements AuthorizeDao {

    @Autowired
    HiberAdd hiberAdd;

    @Override
    public boolean doAuthorize(Authentication authentication) {
        System.out.println("Name: " + authentication.getUserName());
        System.out.println("PW: " + authentication.getPassWord());
        User user = new User();
        user.setId(1212);
        user.setName(authentication.getUserName());
        user.setPasswd(authentication.getPassWord());
        hiberAdd.add(user);
        return true;
    }
}

そして、これは私のCRUDクラスです

`@Service("hiberAdd")
@Transactional
public class HiberAdd {

     @Resource(name="sessionFactory")
 private SessionFactory sessionFactory;
     public void add(User user) {


  // Retrieve session from Hibernate
  Session session = sessionFactory.getCurrentSession();

  // Save
        session.save(user);
         System.out.println("Saved ......................... ");
 }
}`


これは私のエンティティクラスです

`@Entity
@Table(name="User")
public class User implements Serializable{

    @Id
    @Column(name="ID")
    private Integer id;

    @Column(name="UserName")
    private String name;

    @Column(name="passwd")
    private String passwd;
//getters setters
4

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