1

サブクエリで親クエリ列をどのように参照しますか? これが私のクエリです

    SELECT 
    c.username, c.staff_of, CONCAT(c.first_name, ' ', c.middle_name, ' ', c.last_name ) AS csr, 
    d.date, d.account, d.total_transaction, d.total_participate, d.total_amount,
    (SELECT COUNT(id) FROM users WHERE created_by = c.username ) AS total_agents
FROM `users` c,   
    (SELECT
          DATE(res_date) AS date, B.res_account AS account,
          COUNT(B.res_id) AS total_transaction,
          COUNT(DISTINCT(B.res_account)) AS total_participate,
          SUM(B.res_amount) AS total_amount
     FROM
          merchant_responses B
     WHERE B.res_account IN (SELECT t.staff_of FROM users t WHERE t.created_by = c.username)
     ) AS d
WHERE c.account_type ='DSO' GROUP BY c.username

これが得られた結果です

#1054 - Unknown column 'c.username' in 'where clause'

サブクエリで c.username を表示するにはどうすればよいですか?

事前にサンクス

4

2 に答える 2

3

それはサブクエリではなく、派生テーブルです。

 SELECT 
    c.username, c.staff_of, CONCAT(c.first_name, ' ', c.middle_name, ' ', c.last_name ) AS csr, 
    d.date, d.account, d.total_transaction, d.total_participate, d.total_amount,
    (SELECT COUNT(id) FROM users WHERE created_by = c.username ) AS total_agents
FROM `users` c,   
    (SELECT
          DATE(res_date) AS date, B.res_account AS account,
          COUNT(B.res_id) AS total_transaction,
          COUNT(DISTINCT(B.res_account)) AS total_participate,
          SUM(B.res_amount) AS total_amount
     FROM
          merchant_responses B
     WHERE B.res_account IN (SELECT t.staff_of FROM users t)
     ) AS d
WHERE c.account_type ='DSO' AND d.account = c.staff_of GROUP BY c.username

更新されました クエリを更新しました

于 2013-05-03T12:48:06.323 に答える