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私は PHP の初心者で、Web で見つけたチュートリアルを使用して、構築中の新しい CMS の新しい部分を操作しています。問題は、チュートリアルが正常に機能することですが、それを自分の用途に合わせて変更し始めると、データベースに接続して更新できません。「データベース エラー: レコードを更新できません」というエラーが表示されます。追加と削除はできますが、更新はできません。

インデックス.php

    <html>
    <head>
        <title>MySQLi Tutorial</title>

    </head>
<body>

<?php
//include database connection
include 'db_connect.php';

$action = isset($_GET['action']) ? $_GET['action'] : "";

if($action=='delete'){ //if the user clicked ok, run our delete query

    $query = "DELETE FROM family WHERE fid = ".$mysqli->real_escape_string($_GET['fid'])."";
    if( $mysqli->query($query) ){
        echo "User was deleted.";
    }else{
        echo "Database Error: Unable to delete record.";
    }

}

$query = "SELECT * FROM family";
$result = $mysqli->query( $query );

$num_results = $result->num_rows;

echo "<div><a href='add.php'>Create New Record</a></div>";

if( $num_results ){

    echo "<table border='1'>";//start table
    //creating our table heading
    echo "<tr>";
        echo "<th>name</th>";
        echo "<th>Action</th>";
    echo "</tr>";

    //loop to show each records
    while( $row = $result->fetch_assoc() ){
            //extract row
            //this will make $row['firstname'] to
            //just $firstname only
            extract($row);

            //creating new table row per record
            echo "<tr>";
                echo "<td>{$name}</td>";
                echo "<td>";
                    echo "<a href='edit.php?fid={$fid}'>Edit</a>";
                    echo " / ";
                    echo "<a href='#' onclick='delete_user( {$fid} );'>Delete</a>";
                echo "</td>";
            echo "</tr>";
    }

    echo "</table>";//end table

}else{
    //if table is empty
    echo "No records found.";
}

//disconnect from database
$result->free();
$mysqli->close();

?>

<script type='text/javascript'>

    function delete_user( fid ){
        //this script helps us to

        var answer = confirm('Are you sure?');
        if ( answer ){ //if user clicked ok
            //redirect to url with action as delete and fid to the record to be deleted
            window.location = 'index.php?action=delete&fid=' + fid;
        } 
    }
</script>

</body>
</html>

add.php

<html>
    <head>
        <title>MySQLi Create Record</title>

    </head>
<body>
<!--we have our html form here where user information will be entered-->
<form action='#' method='post' border='0'>
    <table>
        <tr>
            <td>Firstname</td>
            <td><input type='text' name='name' /></td>
        </tr>

            <td></td>
            <td>
                <input type='hidden' name='action' value='create' />
                <input type='submit' value='Save' />

                <a href='index.php'>Back to index</a>
            </td>
        </tr>
    </table>
</form>
<?php
$action = isset($_POST['action']) ? $_POST['action'] : "";

if($action=='create'){
    //include database connection
    include 'db_connect.php';

    //write query
    $query = "insert into family 
                set
                name = '" . $mysqli->real_escape_string($_POST['name']) ."'
                    ";

    if( $mysqli->query($query) ) {
        echo "User was created.";
    }else{
        echo "Database Error: Unable to create record.";
    }
    $mysqli->close();
}

?>



</body>
</html>

edit.php

<?php
//include database connection
include 'db_connect.php';

$action = isset( $_POST['action'] ) ? $_POST['action'] : "";
if($action == "update"){
    //write query
    $query = "update users 
                set
                    name = '".$mysqli->real_escape_string($_POST['name'])."', 
                    where 
                    fid='".$mysqli->real_escape_string($_REQUEST['fid'])."'";

    if( $mysqli->query($query) ) {
        echo "User was updated.";
    }else{
        echo "Database Error: Unable to update record.";
    }
}

$query = "select fid, name 
            from family
            where fid='".$mysqli->real_escape_string($_REQUEST['fid'])."'
            limit 0,1";

$result = $mysqli->query( $query );
$row = $result->fetch_assoc();

$fid = $row['fid'];
$name = $row['name'];
?>
<!--we have our html form here where new user information will be entered-->
<form action='#' method='post' border='0'>
    <table>
        <tr>
            <td>Firstname</td>
            <td><input type='text' name='name' value='<?php echo $name;  ?>' /></td>
        </tr>

        <tr>
            <td></td>
            <td>
                <!-- so that we could identify what record is to be updated -->
                <input type='hidden' name='fid' value='<?php echo $fid ?>' /> 

                <!-- we will set the action to edit -->
                <input type='hidden' name='action' value='update' />
                <input type='submit' value='Edit' />

                <a href='index.php'>Back to index</a>
            </td>
        </tr>
    </table>
</form>

>

これを修正するための適切な言語を見つけることができませんでしたが、何らかの形式の倍数を使用しているためだと思いますが、それを修正するための mysqli/php 言語に慣れていません。

ありがとうございました

4

1 に答える 1

0

次の末尾にあるコンマを削除する必要があります。

name = '".$mysqli->real_escape_string($_POST['name'])."',

クエリは次のようになります。

$query = "update users 
            set
                name = '".$mysqli->real_escape_string($_POST['name'])."'
                where 
                fid='".$mysqli->real_escape_string($_REQUEST['fid'])."'";
于 2013-05-10T03:02:10.987 に答える