10

If you run the following code in the Groovy console it prints "8"

class F {

  private final Integer val = 2

  def set(v) {val = v}

  def print() {println val}
}

def f = new F()
f.set(8)
f.print()

In Java this code wouldn't compile because you can't assign a final reference after the constructor has run. I know that for properties, final indicates that the property can't be changed outside the class, but what does it mean to mark a private field final?

Thanks, Don

4

1 に答える 1

2

これは Groovy のバグのようです:

val初期化後に割り当て可能であるべきではないと思います。

于 2009-10-30T20:43:04.843 に答える