13

JSON 形式の日付文字列があります。次のようになります: 2013-05-22T10:54:40.437

そして、それをNSDateに変換しようとしています。

- (NSString *)dateFromString:(NSString *)datestring{
    // Convert string to date object
    NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
    [dateFormat setDateFormat:@"yyyy'-'MM'-'dd'T'HH':'mm':'ss"];

    NSDate *date = [dateFormat dateFromString:datestring];
    //date is nil here.
    NSDateFormatter *newDateFormatter = [[NSDateFormatter alloc]init];
    [newDateFormatter setDateFormat:@"MM/dd/yyyy"];
    NSString *newString = [newDateFormatter stringFromDate:date];
    NSLog(@"Date -- %@",datestring);


    return newString;
}

ただし、dateFromString の後の日付は nil です。ここで私が何を間違えたか知っている人はいますか？ありがとう！

4

4 に答える 4

2 
If your date format is "2014-02-25T13:05:10+00:00" then,
your code should be like this....

    NSURL *url = [NSURL URLWithString:@"your URL"];
    NSString *str = [[NSString alloc] initWithContentsOfURL:url usedEncoding:Nil error:Nil];

    NSDateFormatter *dateFor = [[NSDateFormatter alloc] init];
    [dateFor setDateFormat:**@"yyyy-MM-dd'T'HH:mm:ss'+'SS:SS"**];

    NSDate *yourDate = [dateFor dateFromString:str];
    NSLog(@"Your Date: %@",yourDate);
于 2014-02-25T13:16:59.337 に答える
2 
-(void)viewDidLoad {

    self.date = [dateForRFC3339DateTimeString:@"2015-01-18T01:00:00.000Z"];

}


-(NSDate *)dateForRFC3339DateTimeString:(NSString *)rfc3339DateTimeString {

    NSDateFormatter *rfc3339DateFormatter = [[NSDateFormatter alloc] init];

    [rfc3339DateFormatter setDateFormat:@"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'SSS'Z'"];
    [rfc3339DateFormatter setTimeZone:[NSTimeZone timeZoneForSecondsFromGMT:0]];

    // Convert the RFC 3339 date time string to a NSDate.
    NSDate *result = [rfc3339DateFormatter dateFromString:rfc3339DateTimeString];
    return result;
}
于 2015-01-13T15:50:41.113 に答える