java - @TableGenerator の initialValue 属性は、JPA ではなく Hibernate で問題を示します

Question

package com.sb.firstjpaexample.pojo;

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.SequenceGenerator;
import javax.persistence.Table;
import javax.persistence.TableGenerator;

  @Entity
  @Table(name = "EMPLOYEE")
  public class Employee {

@Id
@TableGenerator(name = "TABLE_GEN", table = "SEQUENCE_TABLE", pkColumnName = "SEQ_NAME", valueColumnName = "SEQ_COUNT", pkColumnValue = "EMP_SEQ", initialValue = 1001, allocationSize = 5)
@GeneratedValue(strategy = GenerationType.TABLE, generator = "TABLE_GEN")
private int employeeId;

@Column
private String employeeName;
@Column
private String designation;
@Column
private double salary;

public int getEmployeeId() {
    return employeeId;
}

public void setEmployeeId(int employeeId) {
    this.employeeId = employeeId;
}

public String getEmployeeName() {
    return employeeName;
}

public void setEmployeeName(String employeeName) {
    this.employeeName = employeeName;
}

public String getDesignation() {
    return designation;
}

public void setDesignation(String designation) {
    this.designation = designation;
}

public double getSalary() {
    return salary;
}

public void setSalary(double salary) {
    this.salary = salary;
}

}

「この POJO は、JPA では初期値を 1001 としますが、Hibernate では初期値として 1 をとります」 ここでアノテーションを使用してインクリメント ステップを設定する方法をもう 1 つ疑う

私を助けてください、事前に感謝します