8

列がほとんど次のように見える「順序」テーブルがあります。

| order_id | shop_id | order_total | currency | created_at |

ここで、次のようなテーブルを返すクエリを作成したいと思います。

| interval | currency | sum |

interval は日付の間隔、currency は通貨、sum はその間隔内のその通貨のすべての注文の合計です。たとえば、次のようになります。

| 2012-08-12-2012-09-12 | EUR | 540922 |

| 2012-08-12-2012-09-12 | DKK | 43215  |

| 2012-09-12-2012-10-12 | EUR | 123643 |

| 2012-09-12-2012-10-12 | DKK | 0      |

私はすでに通貨を無視するクエリを持っていますが、通貨を考慮に入れる方法がわかりません..何かアイデアはありますか?

Heresは、私が現在使用しているクエリの例です。もちろん、実際のクエリはコードによって生成されます。これは単なる例です。

SELECT CASE
         WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
         WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
         WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
       end AS intrvl,
       Sum(order_total)
FROM   `order` o
WHERE  shop_id = 4
       AND created_at BETWEEN '2012-08-12' AND '2012-11-17'
GROUP  BY CASE
            WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
            WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
            WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
          end

/モルテン

4

1 に答える 1

14

add currency into your select and group by clauses

SELECT CASE
         WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
         WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
         WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
       end AS intrvl,
       currency, 
       Sum(order_total)
FROM   `order` o
WHERE  shop_id = 4
       AND created_at BETWEEN '2012-08-12' AND '2012-11-17'
GROUP  BY CASE
            WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
            WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
            WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
          end,
          currency
于 2013-06-17T12:06:58.430 に答える