次のような文字列配列があります
First[i]
この配列では、値は次のようになります
"00hr:00min:17sec"
"00hr:03min:18sec"
"00hr:05min:25sec"
"01hr:39min:44sec"
今、次のような別の文字列配列を取ります
Secound[j]
"17sec Ago"
"3min Ago"
"5min Ago"
"1hr Ago"
最初の文字列配列を秒の文字列配列に変換するにはどうすればよいですか?
string[] first ={"00hr:00min:17sec",
"00hr:03min:18sec",
"00hr:05min:25sec",
"01hr:39min:44sec"};
string[] second = new string[first.Length];
string pattern = @"([0-9]{2})hr:([0-9]{2})min:([0-9]{2})sec";
for (int i = 0; i < first.Length; i++)
{
Match match = Regex.Match(first[i],pattern);
if (match.Success)
{
int hour = int.Parse(match.Groups[1].Value);
if (hour > 0)
second[i] = hour + "hr ago";
else
{
int min = int.Parse(match.Groups[2].Value);
if (min > 0)
second[i] = min + "min ago";
else
{
int sec = int.Parse(match.Groups[3].Value);
if (sec > 0)
second[i] = sec + "sec ago";
}
}
}
}
System.Text.RegularExpressions を使用します。
Parse
、おそらく正規表現で例えば:
static string SimplifyTime(string value)
{
var match = Regex.Match(value, "([0-9]{2})hr:([0-9]{2})min:([0-9]{2})sec");
if (!match.Success) return value;
int val = int.Parse(match.Groups[1].Value, CultureInfo.InvariantCulture);
if (val > 0) return val + "hr Ago";
val = int.Parse(match.Groups[2].Value, CultureInfo.InvariantCulture);
if (val > 0) return val + "min Ago";
val = int.Parse(match.Groups[3].Value, CultureInfo.InvariantCulture);
return val + "sec Ago";
}
static void Main()
{
string[] values = {
"00hr:00min:17sec",
"00hr:03min:18sec",
"00hr:05min:25sec",
"01hr:39min:44sec"
};
var converted = Array.ConvertAll(values, SimplifyTime);
}