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時間と平均を出力するクエリがあります。唯一の問題は、これを実行している6週間の期間に何も起こらなかった場合、すぐにスキップされることです.その場所にNULLまたはゼロを入れるには、その15分間が必要です。ここに私のクエリがあります:

$staffing_qry = "SELECT MAKETIME(hour(opened_dt),floor(minute(opened_dt)/15)*15,0) AS time, ";
$staffing_qry .= "ROUND(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),1) AS calls, ";
$staffing_qry .= "ROUND(AVG(work_time)/60,1) AS work, ";
$staffing_qry .= "ROUND(AVG(tele_time)/60,1) AS tele, ";
$staffing_qry .= "ROUND(AVG(comm_time)/60,1) AS comm, ";
$staffing_qry .= "ROUND(IFNULL(COUNT(*)/COUNT(DISTINCT DATE(opened_dt)),0)/3,1) AS techs ";
$staffing_qry .= "FROM detail_head ";
$staffing_qry .= "LEFT JOIN detail_detail ON detail_detail.detail_head_uid = detail_head.detail_head_uid ";
$staffing_qry .= "WHERE dayname(opened_dt) = $dow_option $staffing_option $proactive_option $incoming_option ";
$staffing_qry .= "AND (DATE(opened_dt) >= (CURDATE() - INTERVAL 42 DAY))";
$staffing_qry .= "GROUP BY (hour(opened_dt)*100)+floor(minute(opened_dt)/15) ";

提案？

4

1 に答える 1

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解決済み:

if(isset($_REQUEST['date_range'])) {
        $date_range_option = (integer) $_REQUEST['date_range'];
}
于 2013-12-05T20:26:35.673 に答える