0 
    please find below a script in php that that fetch data from my database company, the database is in phpMyadmin

データを取得する安全な方法があることを理解しています。私の質問は、mysql_query の代わりに mysqli を使用してフェッチすることで、以下のコードを改善できますか?

    <?php 
        get results from database. Can I improve the code below using mysqli to fetch instead of mysql_query in the following line?.

                $result = mysql_query("SELECT * FROM customer")
                        or die(mysql_error());   
    tables begins here with the customer id and customer name
                echo "<table >"; 
                echo "<tr>              
                            <th>ID</th>   the customer id
                            <th>Name</th> the customer name
                             </tr>"; 

                // loop through results of database query, displaying them in the table
    the table below display the columns in html using mysql fetch array. all data is displayed.

    while($row = mysql_fetch_array( $result )) { 

                        // echo out the contents of each row into a table  
    my purpose is embed the php in html in another way using msqli 
                        echo "<tr>"; 
                        echo '<td>' . $row['CustomerID'].'</td>'; 
                        echo '<td>' . $row['Name']. '</td>'; 
                       echo "</tr>";  
                }  
                       echo "</table>"; 
        ?> 
my purpose is embed the php in html in another way using msqli
4

1 に答える 1

0

mysqlすべてを次のように置き換えるだけですmysqli

      $result = mysqli_query("SELECT * FROM customer");

      while($row = mysqli_fetch_array( $result )) {

シンプルにしたいなら

それともこうやって...

  /*Your connection info goes here...*/
 $mysqli = new mysqli("localhost", "my_user", "my_password", "world");

 if (mysqli_connect_errno()) {
   printf("Connect failed: %s\n", mysqli_connect_error());
   exit();
    }

  $query = "SELECT * FROM customer";

  if ($result = $mysqli->query($query)) {

   echo "<table ><tr><th>ID</th><th>Name</th></tr>"; 

   /* fetch results by row */
   while ($row = $result->fetch_row()) {
    echo "<tr><td>' . $row['CustomerID'].'</td><td>' . $row['Name']. '</td></tr>'; 
   }

  /* free the result set */
  $result->close();
 }

 /* close the connection */
 $mysqli->close();
于 2013-06-24T19:17:29.273 に答える