sql-server - 2 日間の行数

Question

私のデータは以下の形式です：

employee    order id   date   
a           123         01/06/2013
b           124         02/06/2013 
a           125         02/06/2013 
a           129         02/06/2013

以下の形式のデータが必要です。

employee   day 1    day 2
a           1        2
b           0        1

Answer 1

これを試してみてください -

DECLARE @temp TABLE
(
      dtStart DATETIME
    , employees CHAR(1)
)

INSERT INTO @temp (employees, dtStart) VALUES('a','01/06/2013')
INSERT INTO @temp (employees, dtStart) VALUES('a','01/06/2013')
INSERT INTO @temp (employees, dtStart) VALUES('b','02/06/2013')

SELECT 
       employees
     , day1 = COUNT(CASE WHEN DAY(dtStart) = 1 THEN 1 END)
     , day2 = COUNT(CASE WHEN DAY(dtStart) = 2 THEN 1 END) 
FROM @temp
--WHERE dtStart BETWEEN '01/06/2013' AND '30/06/2013'
GROUP BY employees

Answer 2

これらの行に沿った何かが機能するはずです（固定日数があるかどうかに応じて）：

select employee,
       SUM(CASE WHEN date = '01/06/2013' THEN 1 ELSE 0 END) as day1,
       SUM(CASE WHEN date = '02/06/2013' THEN 1 ELSE 0 END) as day2
from table
group by employee

Answer 3

select distinct employees, 
SUM(CASE WHEN dtStart = '01/06/2013' THEN 1 ELSE 0 END) as day1,
SUM(CASE WHEN dtStart = '02/06/2013' THEN 1 ELSE 0 END) as day2 
from yourTable
group by dtStart,employees

デモを見る