0

json配列をパラメーターとして他のアクティビティに渡しますが、クリックするとすべての値がテキストで表示されます。月曜日にこの画像を参照し
て
くださいpostimg.org/image/8m0f1bjaf/987e8eb4/
文字列内のすべてのものをTextViewで名前だけを表示するにはどうすればよいですか? 今、json配列を解析するにはどうすればよいですか???

Json :

   {
   "student": [
     {
        "id": 1,
        "name": "Monday",
        "dish": "Biryani",
        "Gender": "M",
        "age": 10,
        "birthdate": "23/05/2002"
    },
    {
        "id": 2,
        "name": "Tuesday",
        "dish": "Sandwish",
        "Gender": "M",
        "age": 12,
        "birthdate": "08/01/2000"
    },
    {
        "id": 3,
        "name": "Wednesday",
        "dish": "Chicken Tikka",
        "Gender": "F",
        "age": 14,
        "birthdate": "01/03/1998"
    },

コード：

            try {
                JSONObject mainJson = new JSONObject(result);
                 jsonArray = mainJson.getJSONArray(ARRAY_NAME);
                for (int i = 0; i < jsonArray.length(); i++) {
                     objJson = jsonArray.getJSONObject(i);

                    Item objItem = new Item();

                    objItem.setId(objJson.getInt(ID));
                    objItem.setName(objJson.getString(NAME));
                    myname= objJson.getString(NAME);
                    objItem.setCity(objJson.getString(CITY));
                    objItem.setGender(objJson.getString(GENDER));
                    objItem.setAge(objJson.getInt(AGE));
                    objItem.setBirthdate(objJson.getString(BIRTH_DATE));

                    arrayOfList.add(objItem);

                }
            } catch (JSONException e) {
                e.printStackTrace();
            }

            setAdapterToListview();

        }

    }
 }

 @Override
 public void onItemClick(AdapterView<?> parent, View view, int position,
        long id) {

     if(!jsonArray.isNull(position)){
           Intent intent = new Intent(SeletecDayofweek.this,TodayLunch.class);  
           intent.putExtra("name", jsonArray.optJSONObject(position).toString());
           startActivity(intent);    
     }

}     






                   and get like this


                      Intent intent = getIntent();
    String stringRecd = intent.getStringExtra("name");
4

3 に答える 3

0

JSON のシリアル化 -うんざりです! - 非常に簡単に任意のアクティビティにエキストラとして渡すことができます。

于 2013-07-01T06:48:26.063 に答える
0

JSONParserクラスを書く:

public class JSONParser
{

static InputStream is   = null;
static JSONObject  jObj = null;
static String      json = "";

// constructor
public JSONParser()
{

}

// function get json from url
// by making HTTP POST or GET method
public JSONObject makeHttpRequest(
        String url ,
        String method ,
        List<NameValuePair> params )
{
    Log.d( "JSON" , "making HTTP request" );
    // Making HTTP request
    try
    {

        // check for request method
        if (method == "POST")
        {
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost( url );
            httpPost.setEntity( new UrlEncodedFormEntity( params ) );

            HttpResponse httpResponse = httpClient.execute( httpPost );
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }
        else
            if (method == "GET")
            {
                // request method is GET
                DefaultHttpClient httpClient = new DefaultHttpClient();
                String paramString =
                        URLEncodedUtils.format( params , "utf-8" );
                url += "?" + paramString;
                HttpGet httpGet = new HttpGet( url );

                HttpResponse httpResponse = httpClient.execute( httpGet );
                HttpEntity httpEntity = httpResponse.getEntity();
                is = httpEntity.getContent();
            }

    }
    catch (UnsupportedEncodingException e)
    {
        e.printStackTrace();
    }
    catch (ClientProtocolException e)
    {
        e.printStackTrace();
    }
    catch (IOException e)
    {
        e.printStackTrace();
    }

    try
    {
        BufferedReader reader =
                new BufferedReader( new InputStreamReader(
                        is ,
                        "iso-8859-1" ) , 8 );
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ( ( line = reader.readLine() ) != null)
        {
            sb.append( line + "\n" );
        }
        is.close();
        json = sb.toString();
    }
    catch (Exception e)
    {
        Log.e( "Buffer Error" , "Error converting result " + e.toString() );
    }

    // try parse the string to a JSON object
    try
    {
        jObj = new JSONObject( json );
    }
    catch (JSONException e)
    {
        Log.e( "JSON Parser" , "Error parsing data " + e.toString() );
    }

    // return JSON String
    return jObj;

}
}

これを使用して、必要な値を取得するために簡単に解析できる JSON オブジェクトをフェッチします。

json オブジェクトに他jsonArrayにも多くのオブジェクトがある場合は、ループに入れて解析します。

于 2013-07-01T06:49:44.303 に答える