php - php と mysql を使用して出席用のピボット テーブルを作成する

Question

phpmysqlを使ってこのような出席ビューを作りたい

以下は私の出席表です：

    `CREATE TABLE IF NOT EXISTS `attendance` (
      `aid` int(11) NOT NULL AUTO_INCREMENT,
      `Name_of_Student` varchar(100) COLLATE latin1_general_ci NOT NULL,
      `Class` varchar(20) COLLATE latin1_general_ci NOT NULL,
      `Roll_no` int(11) NOT NULL,
      `Section` varchar(20) COLLATE latin1_general_ci NOT NULL,
      `Status` binary(1) NOT NULL,
      `time` varchar(20) COLLATE latin1_general_ci NOT NULL,
      `Date` date NOT NULL,
      PRIMARY KEY (`aid`)
    ) ENGINE=MyISAM  DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci AUTO_INCREMENT=33 ;

--
-- Dumping data for table `attendance`
--

    INSERT INTO `attendance` (`aid`, `Name_of_Student`, `Class`, `Roll_no`, `Section`, `Status`, `time`, `Date`) VALUES
    (1, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-01'),
    (2, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-01'),
    (3, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-02'),
    (4, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-02'),
    (5, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-03'),
    (6, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-03'),
    (7, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-04'),
    (8, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-04'),
    (9, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-05'),
    (10, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-05'),
    (11, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-06'),
    (12, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-06'),
    (13, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-07'),
    (14, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-07'),
    (15, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Morning', '2013-07-08'),
    (16, 'Zonundanga', 'X', 5, 'A', 'Y', 'Morning', '2013-07-08'),
    (17, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-01'),
    (18, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-01'),
    (19, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-02'),
    (20, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-02'),
    (21, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-03'),
    (22, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-03'),
    (23, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-04'),
    (24, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-04'),
    (25, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-05'),
    (26, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-05'),
    (27, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-06'),
    (28, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-06'),
    (29, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-07'),
    (30, 'Zonundanga', 'X', 5, 'A', 'Y', 'Afternoon', '2013-07-07'),
    (31, 'Lalchhandami', 'X', 1, 'A', 'Y', 'Afternoon', '2013-07-08'),
    (32, 'Zonundanga', 'X', 5, 'A', 'N', 'Afternoon', '2013-07-08');`

試行コードは次のとおりです: SQL:

SELECT * FROM attendance

PHP:

$query = $dbh->query("SELECT * FROM attendance");

$result = $query->fetchAll(PDO::FETCH_OBJ);
$column = [];
foreach($result as $key=>$val){
    $column[$val->Name_of_Student][$val->Date][$val->time] = $val->Status; 
}

$Status = []; 
$hming = [];
?>
<table border="1" align="center" width="100%">
    <tr>
        <th>Name</th>
        <?php foreach($column as $dt=>$vt):             
                $hming[] = $dt;
                foreach($vt as $k=>$v):                     
                    $Status[$k] = $v['Morning'];
                    $Status[$k] = $v['Afternoon'];
                    ?>
        <th colspan="2"><?php echo $k; ?></th>
        <?php endforeach; endforeach; ?>
    </tr>
    <?php foreach($hming as $name): ?>
    <tr>
        <td><?php echo $name; ?></td>
        <?php foreach($Status as $time): ?>
        <td><?php echo $time; ?></td>
        <?php endforeach;?>
    </tr>
    <?php endforeach;?>
</table>

問題は、学生ごとに日付がループしていないことです。

Answer 1

mysql_query を使用してすべてのデータを選択し、データを HTML にダンプします。

Answer 2

あなたはこのように行くことができます：

<table>
<tr><th>Sr no</th><th > .....//all of your table heads </th> </tr>   
<?php

    $query = "select * from `attendance`";
    $result = mysql_query($query);
    $result = mysql_fetch_row($result);
    foreach($result as $result)
    {
       echo "<tr><td>".$result['aid']."</td><td>all of id with index</td></tr>"
    }
    ?> </table>