php - PHP で JSON TV ガイドを解析する

Question

このjsonファイルから以下の値を表示したいです。
titlel
datum_start
datum_end
私はこのコードを使用します:

<?php
$nl1jsonurl='http://www.tvgids.nl/json/lists/programs.php?channels=1';
$nl1jsontext=file_get_contents($nl1jsonurl,true);

$nl1 = json_decode($nl1jsontext);
foreach($nl1->1 as $data)
{
     echo $data->titel . "\n";
     echo $data->datum_start . "\n";
     echo $data->datum_end . "\n";

} 
?>

サンプル JSON:

{
    "1": [
        {
            "db_id": "14612024",
            "titel": "NOS Journaal",
            "genre": "Nieuws/actualiteiten",
            "soort": "",
            "kijkwijzer": "",
            "artikel_id": null,
            "artikel_titel": null,
            "datum_start": "2013-07-05 00:10:00",
            "datum_end": "2013-07-05 00:35:00"
        },
        {
            "db_id": "14642893",
            "titel": "NOS Studio Sportzomer: De Avondetappe",
            "genre": "Sport",
            "soort": "",
            "kijkwijzer": "",
            "artikel_id": "58162",
            "artikel_titel": "Sprinten in Montpellier",
            "datum_start": "2013-07-05 00:35:00",
            "datum_end": "2013-07-05 01:30:00"
        }
    ]
}

Answer 1

これはあなたを助けるかもしれません

<?php 
$nl1jsonurl='http://www.tvgids.nl/json/lists/programs.php?channels=1';
$nl1jsontext=file_get_contents($nl1jsonurl,true);

//decode the content lke this
$nl1 = json_decode($nl1jsontext, TRUE);

//print_r($nl1);

foreach($nl1['1'] as $data)
{
     echo $data['title'] . "\n";
     echo $data['datum_start'] . "\n";
     echo $data['datum_end'] . "\n";

}