0

2 つの文字列を 1 つの要素として Python リストに追加したいと考えています。これは私の問題の簡単な例です:

lowerCase = [['a', 'b', 'c', 'd', 'e']]
newList = []

# Append two pieces of data as a single element
i = 1;
for letter in lowerCase[0]:
    [newList.append(letter), newList.append(i)]
    i += 1

print newList
print len(newList)

私が得るもの:

['a', 1, 'b', 2, 'c', 3, 'd', 4, 'e', 5]
10

私が欲しいもの:

[['a', 1], ['b', 2], ['c', 3], ['d', 4], ['e', 5]]
5
4

3 に答える 3

2

問題はforループにあります。次のように行う必要があります。

for letter in lowerCase[0]:
    newList.append([letter, i])
    i += 1
于 2013-07-08T00:23:06.930 に答える
2

必要なのは

newList.append([letter, i])
于 2013-07-08T00:23:16.997 に答える
0

Take a look at your current code:

[newList.append(letter), newList.append(i)]

This line creates a list out of the output of those two method calls. You don't actually use the list, so you're basically doing:

newList.append(letter)
newList.append(i)

You want to append both elements at once inside of one iterable:

newList.append([letter, i])  
newList.append((letter, i))  # Tuples are faster to create, as they're immutable

Also, you usually don't need to create and increment an i variable by hand. Just use enumerate:

newList = []

for index, letter in enumerate(lowerCase[0], start=1):
    newList.append((letter, index))

Or with a list comprehension:

newList = [(letter, index) for index, letter in enumerate(lowerCase[0], start=1)]
于 2013-07-08T00:29:33.237 に答える