sql - MSSQL での重複の削除

Question

MSSQL TABLE には 3 つの列があります。

ID (IDENTITY), KeptValue(NVARCHAR), SPENT(MONEY).

重複している複数KeptValueの があります。すべての重複を削除して 1 を維持する必要があります。
2 つのビューを作成しました。複製された保持値のリストVW_DUPLICATE1。

Answer 1

delete t1
from your_table t1
left join  
(
   select keptvalue, max(spent) as mSpent
   from your_table
   group by keptvalue

) t2 on t1.keptvalue = t2.keptvalue and t1.spent = t2.mSpent
where t2.mSpent is null

Answer 2

これを試して

DELETE FROM tbl WHERE Id IN (
    SELECT Id FROM (
        SELECT 
            Id
            ,ROW_NUMBER() OVER (PARTITION BY KeptValue ORDER BY SPENT DESC) AS [ItemNumber]
        FROM 
            tbl
    ) a WHERE ItemNumber > 1 
)

Answer 3

これを試して

Create table #temp ( ID int, KeptValue NVARCHAR(20) , SPENT numeric(18,3))

INSERT INTO #temp select 1,'KeptValue1', 20
INSERT INTO #temp select 2,'KeptValue1', 21
INSERT INTO #temp select 3,'KeptValue2', 22
INSERT INTO #temp select 4,'KeptValue2', 20
INSERT INTO #temp select 5,'KeptValue2', 20
INSERT INTO #temp select 6,'KeptValue3', 20
INSERT INTO #temp select 7,'KeptValue3', 23
INSERT INTO #temp select 8,'KeptValue3', 24
INSERT INTO #temp select 9,'KeptValue4', 28
INSERT INTO #temp select 10,'KeptValue4', 23
INSERT INTO #temp select 11,'KeptValue5', 24
INSERT INTO #temp select 12,'KeptValue6', 28

select * FROM #temp 

DELETE 
FROM #temp 
WHERE ID 
in(
    select ID from  
                    (SELECT Id, (ROW_NUMBER() OVER(PARTITION BY KeptValue order by SPENT desc)) as R 
                    from #temp
                    ) as RowsNm
    WHERE R >1)

select * from #temp 


drop table #temp 

Answer 4

このクエリを使用して、特定KepValueの最高値を維持することで削除できますSPENT。

DELETE FROM your_table WHERE SPENT < (SELECT MAX(SPENT) FROM your_table WHERE KeptValue='your_value') AND KeptValue='your_value'

Answer 5

これは、group byKeptValue とmaxSpent の集計を行うことで実現できます。