1

なぜこのコードは：

s = "\x00\x00\x00\x00\x03\x00\x00\x00id\x00\x00"
from Crypto.PublicKey import RSA
from Crypto.Util import randpool
key = RSA.generate(1024, randpool.RandomPool().get_bytes)
d = key.encrypt(s, None)
dec = key.decrypt(d)
print ''.join( [ "%02X " % ord( x ) for x in dec ] ).strip()

出力：

03 00 00 00 69 64 00 00

それ以外の

00 00 00 00 03 00 00 00 69 64 00 00
4

1 に答える 1

2

It happens because the default encryption algorithm adds some leading null-bytes to the message and the decryption algorithm strips all the leading null-bytes even if they were in the original message.

The solution is to use Crypto.Cipher.PKCS1_OAEP for encryption/decryption.

from Crypto.PublicKey import RSA
from Crypto.Util import randpool
from Crypto.Cipher import PKCS1_OAEP as PKCS


s = "\x00\x00\x00\x00\x03\x00\x00\x00id\x00\x00"
key = RSA.generate(1024, randpool.RandomPool().get_bytes)

cipher = PKCS.new(key)
encr = cipher.encrypt(s)
decr = cipher.decrypt(encr)
于 2013-07-09T21:17:36.633 に答える