2

日付と最後の注文日までに顧客が行った注文の総数を見つけたいと思っていました。

お客様

custome_id      customer_name
    1              JOHN
    2              ALEX

注文

order_id       customer_id        order_date      status
   R1              1              06/06/2013      completed
   R2              1              05/29/2013      completed
   B1091           1              01/17/2011      canceled
   B2192           1              12/24/2010      completed

注: order_id は増分ではないため、最後の注文を見つけるのに役立ちません。

私が試しているクエリは

select customer.customer_id, customer.customer_name, order.order_id as last_order_id, max(order.order_date) as maxOrderDate,
  sum( case when order.status='completed' then 1 else 0) as completed_orders,
  count( order_id) as total_orders 
  from customer as customer inner join order as order
  on customer.customer_id = order.customer_id
  where customer.id = 1
  group by customer.customer_id, customer.customer_name, order.order_id

期待される結果として

 customer_id  customer_name  Last_order_id  maxOrderDate   completed_orders   total_orders
    1                JOHN        R1            06/06/2013             3              4
4

4 に答える 4

0 
select
customer_id,
MAX(order_date) as last_order_date,
count(*) as num_orders
from Order
group by customer_id
于 2013-07-10T06:11:22.940 に答える
0 
SELECT o.order_id, o.customer_id, c.customer_name, MAX(o.order_date) 
FROM Order o
INNER JOIN Customer c ON c.custome_id = o.custome_id
WHERE o.status = 'completed'
GROUP BY o.customer_id
ORDER BY o.customer_id ASC;
于 2013-07-10T06:11:48.000 に答える