0

例外をループしようとしていますが、何らかの理由でスキャナーファイルを再書き込みするオプションが表示されません。

BufferedReaderの使い方がわからないので、これを使っています。手がかりはありますか？

これが私のメソッドを持つ私の標準クラスです

package arrayExceptionsWithInput;
import java.util.*;
public class GetThoseNumbersBaby {

    int firstInt;
    int secondInt;
    boolean error;
    Scanner yourNumbers = new Scanner(System.in);

    public void findNumbers()
    {
        System.out.println(" please enter your first number");
        firstInt = yourNumbers.nextInt();
        System.out.println(" pleas enter your second number");
        secondInt = yourNumbers.nextInt();
        int finalInt = (firstInt+secondInt);
        System.out.println("total is: " + finalInt);
    }
}

そして、これが私のメインクラスですが、ループで実装されている例外があります。

package arrayExceptionsWithInput;
import java.util.*;

public class InputException
{
    public static void main(String[] args)
    {
        boolean error = false;
        GetThoseNumbersBaby zack = new  GetThoseNumbersBaby();


        {
            do {
                try
                {
                    zack.findNumbers();
                }
                catch(InputMismatchException Q)
                {
                    System.out.println(" one of your integers was incorrect, please try again");
                    Q.printStackTrace();
                    error = true;
                } 
            } while (error == true);
        }
        error = false;
    }
}

これを別の方法でループする方法について誰かが何かアイデアを持っているなら、私はすべての耳です。

4

3 に答える 3

1

Set error false before the action. That way you have the correct exit condition if the user gets it right.

error = false;
zack.findNumbers();
于 2009-11-19T12:31:32.407 に答える
0

i decided too get rid of the method class and just put the method into the try exception area.

used a .nextLine after scanner and it seems fixed.

this looks ok?

package arrayExceptionsWithInput;
import java.util.*;
public class InputException
{
public static void main(String[] args)
{
boolean error = false;
int firstInt;
int secondInt;
Scanner yourNumbers = new Scanner(System.in);
{
    do{
            try
            {

                    System.out.println(" please enter your first number");
                    firstInt = yourNumbers.nextInt();
                    yourNumbers.nextLine();
                    System.out.println(" pleas enter your second number");
                    secondInt = yourNumbers.nextInt();
                    yourNumbers.nextLine();
                    int finalInt = (firstInt+secondInt);
                    System.out.println("total is: " + finalInt);
                    yourNumbers.nextLine();

            }
            catch(InputMismatchException Q)
            {

                Q.printStackTrace();
                System.out.println(" one of your integers was incorrect, please try again");
                error = true;
                yourNumbers.nextLine();
            }   
        }while (error == true);
    }error = false;
}
}
于 2009-11-19T12:32:06.057 に答える
0

You loop while 'error' variable has value 'true'. However, it becomes 'true' only when the is thrown (i.e. when 'catch' block is executed). Control flow doesn't reach it.

于 2009-11-19T12:34:33.413 に答える