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date_base_start = datetime(2013, 07, 17, 20, 0) #July 17,2013 08:00PM
date_base_end = datetime(2013, 07, 17, 22, 0)   #July 17,2013 10:00PM

date_1_start = datetime(2013, 07, 17, 21, 0)    #July 17,2013 09:00PM
date_1_end = datetime(2013, 07, 17, 21, 30)     #July 17,2013 09:30PM

date_2_start = datetime(2013, 07, 17, 19, 0)    #July 17,2013 07:00PM
date_2_end = datetime(2013, 07, 17, 23, 0)      #July 17,2013 11:00PM

date_3_start = datetime(2013, 07, 17, 19, 0)    #July 17,2013 07:00PM
date_3_end = datetime(2013, 07, 17, 22, 0)      #July 17,2013 10:00PM

#Expected Result date_base_start, date_base_end VS the ff:
#     date_1_start, date_1_end : 30min
#     date_2_start, date_2_end : 120min
#     date_3_start, date_3_end : 120min

この問題を解決するには、どの Python 日時操作が必要ですか?

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3 に答える 3

2 
def overlap(range1,range2):
    start_datetime = max(range1[0],range2[0])
    end_datetime   = min(range1[1],range2[1])
    return end_datetime-start_datetime

print overlap([date_base_start,date_base_end],[date_3_start, date_3_end])
于 2013-07-19T02:12:29.397 に答える