android - AndroidでJSONでデータを送信する際にPOSTを使用するには?

Question

POST を使用して JSON でデータを送信する正しい方法を行っているかどうかはわかりません。JSONObject「ReportCode」で単一のデータを送信したい。私はこれまでにこれを手に入れましたか？コードの何が問題なのか、データを JSON で渡すにはどうすればよいのか教えてください。ありがとう。

public class DoPost extends AsyncTask<String, Void, Boolean>
{
Exception exception = null;
private ProgressDialog progressDialog;
Context mContext = null;
BufferedReader in;
InputStream is;

public DoPost(Context context) {

    mContext = context;

}

protected void onPreExecute() 
{     
    progressDialog = new ProgressDialog(mContext);
    progressDialog.setMessage("Validating....");
    progressDialog.show();              
    progressDialog.setCancelable(false);
}

@Override
protected Boolean doInBackground(String... arg0) 
{
    JSONObject jObject = new JSONObject();
    try{
        jObject.put("ReportCode","13-T001");

        List<NameValuePair> pairs = new ArrayList<NameValuePair>();
        pairs.add(new BasicNameValuePair("ReportData", jObject.toString()));

        DefaultHttpClient httpClient = new DefaultHttpClient();
        HttpPost httpPost = new HttpPost("http://phsjulchs4.tias.com.ph:1217/api/report");
        httpPost.setEntity(new UrlEncodedFormEntity(pairs, "UTF-8"));
        HttpResponse httpResponse = httpClient.execute(httpPost);
        HttpEntity httpEntity = httpResponse.getEntity();
        is = httpEntity.getContent();


    }catch (Exception e){
    Log.e("ClientServerDemo", "Error:", e);
    exception = e;
    //Toast.makeText(getApplicationContext(), e.getMessage().toString(), 5).show();
    }

return true;    

}

@Override
protected void onPostExecute(Boolean valid)
{
    progressDialog.dismiss();   
    //Update the UI
    if(exception != null){

        Toast.makeText(mContext, "Sent", 6).show();
    }else{
    //  mContext.startActivity(new Intent(mContext, S_2nd_Main.class));

    }
}

}