c++ - イテレータの問題をマップします。コードが含まれています

Question

ここにすべてのコードがありますが、これらのエラーが発生する理由がよくわかりません。問題は、レシピのエクスポート機能内にあります。

#include<iostream>
#include<fstream>
#include<map>
#include<vector>
#include<string>


using namespace std;

void DisplayMenu();
void AddRecipe( map< string, vector<string> >& recipes );
void ExportRecipes( map< string, vector<string> >& recipes );

int main ( void ){

   int choice = 0;
   bool done = false;
   map< string, vector<string> > recipes;

    while ( done == false ){
       DisplayMenu();
       cin >> choice;

       if ( choice == 3 ){
        done = true;
       }
       else if ( choice == 2 ){
        ExportRecipes( recipes );
       }
       else if ( choice == 1 ){
        AddRecipe( recipes );
       }

    }
}

void DisplayMenu(){ 
   cout << "1. Add Recipe " << endl;
   cout << "2. Export Recipes " << endl;
   cout << "3. Exit" << endl;
}

void AddRecipe( map< string, vector<string> >& recipes ){

   string name, ingredient;
   bool done = false;
   cout << "Enter recipe name: ";
   cin >> name;
   while ( done == false ){     
       cout  << "Enter new ingredient and amount( enter done to exit )" << endl;
       getline( cin , ingredient, '\n' );

       if ( ingredient == "done" ){
           done = true;
       }

       if( ingredient != "done"){
           recipes[ name ].push_back( ingredient );
           cout << "Added \"" << ingredient << "\"." << endl << endl;
       }        
   }
}


void ExportRecipes(  map< string, vector<string> >&recipes ){

   ofstream outFile;
   outFile.open( "Recipes.txt" );

   for ( map< string, vector<string> >::iterator recipe =
       recipes.begin(); recipe != recipes.end(); recipe++ ) {
       outFile << endl << endl << recipe -> first << endl;

       for ( map< string, vector<string> >::iterator ingredients = 
           recipe->second.begin(); ingredients != recipe->second.end();
            ingredients++ ) {
               outFile << "\t" << *ingredients << endl;
       }
   }
}

エクスポートの最初の for ループだけを反復すると、キーを取得できますが、値をまったく取得できません。