python - Pandas write_frame は sqlite テーブルを削除します

Question

Pandas の内容で sqlite テーブルを上書きしようとすると、Pandas はテーブルを上書きしますdataframeがDROP、INSERT.

最小限の作業例を次に示します。

import sqlite3 as sq
import pandas as pd
import pandas.io.sql as pd_sql

d = pd.DataFrame({'year':[2008,2008,2008,2008,2009,2009,2009,2009], 
                  'flavour':['strawberry','strawberry','banana','banana',
                  'strawberry','strawberry','banana','banana'],
                  'day':['sat','sun','sat','sun','sat','sun','sat','sun'],
                  'sales':[10,12,22,23,11,13,23,24]})

# Connect to the database (create if necessary)                  
conn = sq.connect('mydb')

# Create the table 'mytable' if necessary
if not pd_sql.table_exists('mytable', conn, 'sqlite'):
    pd_sql.write_frame(d, 'mytable', conn)

# Change some data    
d['sales'][d.sales==24] = 25

# Confirm the table exists
print "Table 'mytable' exists:"
print pd_sql.table_exists('mytable', conn, 'sqlite')

# Get some data from the table
cur = pd_sql.execute("SELECT DISTINCT flavour FROM mytable", conn)
print "Here's the data to prove the table exists:"
print cur.fetchall()

try:
    print "Attempting write_frame..."
    pd_sql.write_frame(d, 'mytable', conn, if_exists='replace')
except sq.OperationalError as e:
    print "sq.OperationalError is: " + str(e)
    print pd_sql.table_exists('mytable', conn, 'sqlite')
    conn.close()

このスクリプトを実行すると、次の出力が得られます。

Table 'mytable' exists:
True
Here's the data to prove the table exists:
[(u'banana',), (u'strawberry',)]
Attempting write_frame...
sq.OperationalError is: no such table: mytable
Table 'mytable' exists after write_frame:
False

これはパンダのバグのようです。誰でもこれを確認できますか？

いつもありがとう、ロブ