最近、私はPythonで単語ゲームに取り組んでいますが、それにもかかわらず、少し詳細に問題があります.ゲームのアイデアは、ランダムに与えられた手で文字を使って単語を作成することです. ゲームをコーディネートする機能は、ユーザーに文字の入力を求め、それに従って新しいハンドをプレイしたり、同じハンドを再プレイしたり、ゲームを終了したりします。問題は、ゲームを前のハンドに戻して、ユーザーにもう一度プレイさせることができないことです。代わりに、コードは前の手を修正したバージョンを返すため、単語を正しく入力した場合、その単語の文字は含まれません。「手札を更新する」という機能は別のスコープにあるので、これは不可能だと思いました。私はpython 3.2.1で作業しています
コード全体を投稿して、テストしてその動作を確認できるようにしました。ただし、問題は次の関数にあります: play_game、play_hand、および update_hand。
import random
import string
VOWELS = 'aeiou'
CONSONANTS = 'bcdfghjklmnpqrstvwxyz'
HAND_SIZE = 7
SCRABBLE_LETTER_VALUES = {
'a': 1, 'b': 3, 'c': 3, 'd': 2, 'e': 1, 'f': 4, 'g': 2, 'h': 4, 'i': 1, 'j': 8, 'k': 5, 'l': 1, 'm': 3, 'n': 1, 'o': 1, 'p': 3, 'q': 10, 'r': 1, 's': 1, 't': 1, 'u': 1, 'v': 4, 'w': 4, 'x': 8, 'y': 4, 'z': 10
}
WORDLIST_FILENAME = "words.txt"
def load_words():
"""
Returns a list of valid words. Words are strings of lowercase letters.
Depending on the size of the word list, this function may
take a while to finish.
"""
print ("Loading word list from file...")
# inFile: file
inFile = open(WORDLIST_FILENAME, 'r')
# wordlist: list of strings
wordlist = []
for line in inFile:
wordlist.append(line.strip().lower())
print (" ", len(wordlist), "words loaded.")
return wordlist
def get_frequency_dict(sequence):
"""
Returns a dictionary where the keys are elements of the sequence
and the values are integer counts, for the number of times that
an element is repeated in the sequence.
sequence: string or list
return: dictionary
"""
# freqs: dictionary (element_type -> int)
freq = {}
for x in sequence:
freq[x] = freq.get(x,0) + 1
return freq
def get_word_score(word, n):
"""
Returns the score for a word. Assumes the word is a
valid word.
The score for a word is the sum of the points for letters
in the word multiplied by the length of the word, plus 50
points if all n letters are used on the first go.
Letters are scored as in Scrabble; A is worth 1, B is
worth 3, C is worth 3, D is worth 2, E is worth 1, and so on.
word: string (lowercase letters)
returns: int >= 0
"""
score = 0
for character in word:
score = score + (SCRABBLE_LETTER_VALUES[character])
score = score * len(word)
if len(word) == 7:
score = score + 50
return score
def display_hand(hand):
"""
Displays the letters currently in the hand.
For example:
display_hand({'a':1, 'x':2, 'l':3, 'e':1})
Should print out something like:
a x x l l l e
The order of the letters is unimportant.
hand: dictionary (string -> int)
"""
for letter in hand.keys():
for j in range(hand[letter]):
print (letter,)
def deal_hand(n):
"""
Returns a random hand containing n lowercase letters.
At least n/3 the letters in the hand should be VOWELS.
Hands are represented as dictionaries. The keys are
letters and the values are the number of times the
particular letter is repeated in that hand.
n: int >= 0
returns: dictionary (string -> int)
"""
hand={}
num_vowels = int(n / 3)
for i in range(num_vowels):
x = VOWELS[random.randrange(0,len(VOWELS))]
hand[x] = hand.get(x, 0) + 1
for i in range(num_vowels, n):
x = CONSONANTS[random.randrange(0,len(CONSONANTS))]
hand[x] = hand.get(x, 0) + 1
return hand
def update_hand(hand, word):
"""
Assumes that 'hand' has all the letters in word.
In other words, this assumes that however many times
a letter appears in 'word', 'hand' has at least as
many of that letter in it.
Updates the hand: uses up the letters in the given word
and returns the new hand, without those letters in it.
Has no side effects: does not modify hand.
word: string
hand: dictionary (string -> int)
returns: dictionary (string -> int)
"""
for i in word:
new_hand = hand
new_VOWELS = VOWELS
new_CONSONANTS = CONSONANTS
if i in VOWELS:
new_VOWELS = new_VOWELS.replace("i", "")
new_hand[i] = new_hand.get(i, 0) - 1
if new_hand[i] <= 0:
new_hand.pop(i, None)
else:
new_CONSONANTS = new_CONSONANTS.replace("i", "")
new_hand[i] = new_hand.get(i, 0) - 1
if new_hand[i] <= 0:
new_hand.pop(i, None)
return (new_hand)
def is_valid_word(word, hand, word_list):
"""
Returns True if word is in the word_list and is entirely
composed of letters in the hand. Otherwise, returns False.
Does not mutate hand or word_list.
word: string
hand: dictionary (string -> int)
word_list: list of lowercase strings
"""
for character in word:
x = 0
if character in hand:
x = x + 1
if (x==(len(word)-1)) and (word in word_list):
return (True)
else:
return (False)
def calculate_handlen(hand):
handlen = 0
for v in hand.values():
handlen += v
return handlen
def play_hand(hand, word_list):
"""
Allows the user to play the given hand, as follows:
* The hand is displayed.
* The user may input a word.
* An invalid word is rejected, and a message is displayed asking
the user to choose another word.
* When a valid word is entered, it uses up letters from the hand.
* After every valid word: the score for that word is displayed,
the remaining letters in the hand are displayed, and the user
is asked to input another word.
* The sum of the word scores is displayed when the hand finishes.
* The hand finishes when there are no more unused letters.
The user can also finish playing the hand by inputing a single
period (the string '.') instead of a word.
hand: dictionary (string -> int)
word_list: list of lowercase strings
"""
score = 0
han = hand
while True:
print ("Score= ", score)
word = str(input("Enter your word: "))
value = is_valid_word(word, han, word_list)
if value == True:
print ("Congratulations, that word is worth", get_word_score(word, 7), "points")
print ("Please input another word")
han = update_hand(han, word)
print ("Current hand=")
display_hand(han)
score = score + get_word_score(word, 7)
elif word == "." or len(hand)==0:
break
else:
print ("Current hand=")
display_hand(han)
print ("Sorry, that word is not valid")
print ("Please choose another word")
def play_game(word_list):
"""
Allow the user to play an arbitrary number of hands.
* Asks the user to input 'n' or 'r' or 'e'.
* If the user inputs 'n', let the user play a new (random) hand.
When done playing the hand, ask the 'n' or 'e' question again.
* If the user inputs 'r', let the user play the last hand again.
* If the user inputs 'e', exit the game.
* If the user inputs anything else, ask them again.
"""
global handy
handy = deal_hand(7)
while True:
print ("Use 'n' to play a new hand, 'r' to play the last hand again or 'e' to exit game")
inp = str(input("Enter a letter:'n' or 'r' or 'e': ="))
if inp == 'n':
hand = deal_hand(7)
handy = hand
print("Current hand =")
display_hand(hand)
play_hand(hand, word_list)
elif inp == 'r':
print("Current hand =")
display_hand(handy)
play_hand(handy, word_list)
elif inp == 'e':
exit(play_game)
else:
print ("Please input a valid letter")
if __name__ == '__main__':
word_list = load_words()
play_game(word_list)