1

list1 または list2 の各リストを「[ ]」を含まない列として印刷するにはどうすればよいですか?

import csv
def test():
    list1 = [[1, 2, 3, 4], [3, 2, 5], [9, 3, 6, 8, 4]]
    list2 = [[2, 2, 4, 4], [1, 9, 10], [2, 7, 7, 4, 5]]
    with open('doc.csv', 'w', newline='') as file:
        writer = csv.writer(file, quotechar='"', quoting=csv.QUOTE_ALL)
        writer.writerow(list1)
        writer.writerow(list2)
if __name__ == '__main__':
    test()

これは私が望むものに近いですが、文字列に [ ] があります:

[1, 2, 3, 4],[3, 2, 5],[9, 3, 6, 8, 4]
[2, 2, 4, 4],[1, 9, 10],[2, 7, 7, 4, 5]

編集：

私が欲しい：

"1, 2, 3, 4","3, 2, 5","9, 3, 6, 8, 4"
"2, 2, 4, 4","1, 9, 10","2, 7, 7, 4, 5"
4

2 に答える 2

1

これは私がそれを行う方法です：

import csv

def nested_list_formatter(nested):
    return tuple(','.join(str(item) for item in sublist) for sublist in nested)

def test():
    list1 = [[1, 2, 3, 4], [3, 2, 5], [9, 3, 6, 8, 4]]
    list2 = [[2, 2, 4, 4], [1, 9, 10], [2, 7, 7, 4, 5]]
    with open('doc.csv', 'w', newline='') as file:
        writer = csv.writer(file, quotechar='"', quoting=csv.QUOTE_ALL)
        writer.writerow(nested_list_formatter(list1))
        writer.writerow(nested_list_formatter(list2))

if __name__ == '__main__':
    test()

の結果の内容doc.csv:

"1,2,3,4","3,2,5","9,3,6,8,4"
"2,2,4,4","1,9,10","2,7,7,4,5"
于 2013-08-16T20:27:25.750 に答える